Mysql 从2列中选择唯一值

我正在寻找一个SQL查询，它选择x行，其中的列最终只有唯一的值

这张桌子叫keezdrives_played 这些列称为：团队id和对手id

[数据库图片][1]

它应该是这样的： [示例][2]

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当团队id和对手id具有唯一值时，您可以使用如下查询：

SELECT t.team_id ,o.opponents_id FROM yourTAble t
INNER JOIN (
    SELECT team_id,opponents_id FROM yourTAble
    GROUP BY opponents_id
    HAVING count(*) = 1
) AS o ON o.team_id = t.team_id
GROUP BY t.team_id 
HAVING count(*) = 1;

样本

mysql> select * from yourTable;
+---------+--------------+
| team_id | opponents_id |
+---------+--------------+
|       1 |            5 |
|       1 |            6 |
|       2 |            7 |
|       2 |           80 |
|       3 |            9 |
|       4 |           11 |
|       4 |           22 |
|       8 |            5 |
+---------+--------------+
8 rows in set (0,00 sec)

mysql>     SELECT t.team_id ,o.opponents_id FROM yourTAble t
    ->     INNER JOIN (
    ->         SELECT team_id,opponents_id FROM yourTAble
    ->         GROUP BY opponents_id
    ->         HAVING count(*) = 1
    ->     ) AS o ON o.team_id = t.team_id
    ->     GROUP BY t.team_id
    ->     HAVING count(*) = 1;
+---------+--------------+
| team_id | opponents_id |
+---------+--------------+
|       3 |            9 |
+---------+--------------+
1 row in set (0,00 sec)

mysql>

SELECT  team_id,opponents_id
FROM keezdrives_played
GROUP BY CONCAT(team_id, '-', opponents_id)
HAVING count(*) = 1;

见评论

mysql> SELECT count(*) AS cnt , team_id
    -> FROM keezdrives_played
    -> GROUP BY team_id
    -> ;
+-----+---------+
| cnt | team_id |
+-----+---------+
|   4 |    2281 |
|   4 |    2282 |
|   4 |    2283 |
|   4 |    2284 |
|   4 |    2285 |
|   4 |    2286 |
+-----+---------+
6 rows in set (0,00 sec)

mysql>

再试一次

mysql> select * from yourTable;
+---------+--------------+
| team_id | opponents_id |
+---------+--------------+
|       1 |            5 |
|       1 |            6 |
|       2 |            7 |
|       2 |           80 |
|       3 |            9 |
|       4 |           11 |
|       4 |           22 |
|       8 |            5 |
+---------+--------------+
8 rows in set (0,00 sec)

mysql>     SELECT t.team_id ,o.opponents_id FROM yourTAble t
    ->     INNER JOIN (
    ->         SELECT team_id,opponents_id FROM yourTAble
    ->         GROUP BY opponents_id
    ->         HAVING count(*) = 1
    ->     ) AS o ON o.team_id = t.team_id
    ->     GROUP BY t.team_id
    ->     HAVING count(*) = 1;
+---------+--------------+
| team_id | opponents_id |
+---------+--------------+
|       3 |            9 |
+---------+--------------+
1 row in set (0,00 sec)

mysql>

SELECT  team_id,opponents_id
FROM keezdrives_played
GROUP BY CONCAT(team_id, '-', opponents_id)
HAVING count(*) = 1;

最后一次尝试

SELECT * FROM (
    SELECT t.team_id ,t.opponents_id 
    FROM keezdrives_played t
    GROUP BY t.team_id
    ) r
GROUP BY r.opponents_id;

---

我希望这就是你想要的

SELECT DISTINCT team_id ,opponents_id  FROM keezdrives_played where drive_id=144;

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在完成这两个步骤后，使用distinct（oppents_id）。这是第一步，然后第二步是不同的第一步结果，然后你得到了你的结果。由于这个原因，您必须需要子查询。我希望如果您使用子查询，那么您将获得正确的结果将示例表作为sql转储发布，以帮助您我已将其添加到我的答案中。您可以看到团队id不是唯一的。每个条目有4行。您是否只寻找这两个字段的唯一组合？我已添加一次尝试，在这两个字段上提供所有唯一性fields@shampally-再一次-最后一次测试