Mysql 基于DB值返回的限制结果

我有两个表格、类别和故事

“故事”表包含按类别组织的内容

categories_id, category_name, category_story_count
1, news, 2
2, funnies, 3

stories_id, categories_id, story_name, story_content, story_active
1, 1, "Tax Hike", "blah blah", 1
2, 1, "Tax Cuts", "blah blah", 1
2, 1, "Election", "blah blah", 1 
4, 2, "Peanuts", "blah blah", 1
5, 2, "Garfield", "blah blah", 1
6, 2, "Archie", "blah blah", 1 

我想要一个查询，它将根据category\u story\u计数返回每个类别的正确故事数，并且如果故事是活动的，那么story\u active=1

因此，结果应该如下所示：

"news", "Tax Hike"
"news", "Tax Cuts"
"funnies", "Peanuts"
"funnies", "Garfield"
"funnies", "Archie"

两个新闻故事，因为新闻类别1，有一个类别故事计数=2，三个搞笑，因为搞笑2，有一个类别故事计数=3

我尝试过内部连接、嵌套和限制，但就是无法让它返回我的目标

任何帮助都将不胜感激

编辑： MySQL版本

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8.0.23以下是一个使用窗口功能的解决方案：

with cte as ( 
  select *, row_number() over (partition by c.categories_id order by s.stories_id) as rownum 
  from Categories as c join Stories as s using (categories_id) 
) select * from cte where rownum <= category_story_count;

+---------------+---------------+----------------------+------------+------------+---------------+--------------+--------+
| categories_id | category_name | category_story_count | stories_id | story_name | story_content | story_active | rownum |
+---------------+---------------+----------------------+------------+------------+---------------+--------------+--------+
|             1 | new           |                    2 |          1 | Tax Hike   | blah blah     |            1 |      1 |
|             1 | new           |                    2 |          2 | Tax Cuts   | blah blah     |            1 |      2 |
|             2 | funnies       |                    3 |          4 | Peanuts    | blah blah     |            1 |      1 |
|             2 | funnies       |                    3 |          5 | Garfield   | blah blah     |            1 |      2 |
|             2 | funnies       |                    3 |          6 | Archie     | blah blah     |            1 |      3 |
+---------------+---------------+----------------------+------------+------------+---------------+--------------+--------+

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在MySQL 8.0.23上测试。

您使用的MySQL版本是什么？也就是说，选择什么版本；回来如果您使用MySQL 8.0.VERSION 8.0.23，可能会有一个带有窗口函数的解决方案