Mysql Yii2使用ActiveRecord的三个表之间的关系

我在mysql数据库中有三个表，如下图所示：

现在，通过gii，我创建了如下模型：

$model = $this->findModel($id); // model Bukti Penerimaan.
$dataInvoice  = $model->invoiceReports; //exist
$dataInvoiceDetail = $model->invoiceReports->invoiceReportDetails // failed, always null.

对于Buktipeneriman表

class BuktiPenerimaan extends \yii\db\ActiveRecord{
/**
 * @return \yii\db\ActiveQuery
 */
public function getInvoiceReports()
{
    return $this->hasMany(InvoiceReport::className(), ['bukti_penerimaan_id' => 'id']);
}
}

和发票报告：

class InvoiceReport extends \yii\db\ActiveRecord{

/**
 * @return \yii\db\ActiveQuery
 */
public function getInvoiceReportDetails()
{
    return $this->hasMany(InvoiceReportDetail::className(), ['invoice_id' => 'id']);
}

我的问题是，如果我创建了一个来自Buktipeneriman的对象，如何访问表

invoice\u report\u detail

中的所有记录

我是这样使用的：

$model = $this->findModel($id); // model Bukti Penerimaan.
$dataInvoice  = $model->invoiceReports; //exist
$dataInvoiceDetail = $model->invoiceReports->invoiceReportDetails // failed, always null.

---

请注意

$dataInvoice=$model->invoiceReports

是

InvoiceReport

对象的数组

您需要在每个

InvoiceReport

上循环以获取相关的

InvoiceReportDetail

$model = $this->findModel($id); // model Bukti Penerimaan.
$dataInvoice  = $model->invoiceReports; //exist , but array of objects
$dataInvoiceDetail = [];
foreach($dataInvoice as $dInvoice):
   $dataInvoiceDetail[] = array_merge($dataInvoiceDetail,$dInvoice->invoiceReportDetails );
endforeach;
// $dataInvoiceDetail contains all invoice_report_detail