如何根据MySQL中的两个不同条件从同一列中检索两个值？

表名：路由

Route_ID (int)
Route_From (int)
Route_To (int)

表名：车站

Station_ID (int),
Name (char)

Route\u From

、

Route\u To

和

Station\u ID

的值相同

我想知道如何从stations.name中检索两个不同条件下的值。比如说

 select s.name, s.name from stations s, route r, 
 where route_from=1 and
 route_to=3;

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我该怎么做？

也许你可以这样做：

SELECT
    Route.Route_ID,
    fromStation.Name,
    toStation.Name
FROM
    Route
    LEFT JOIN Stations AS fromStation
        ON Route.Route_From =fromStation.Station_ID
    LEFT JOIN Stations AS toStation
        ON Route.Route_To  =toStation.Station_ID
WHERE 
    Route.Route_ID = 1;

select s1.name as route_from, s2.name as route_to from route r
left join stations s1 on r.route_from = s1.Station_ID
left join stations s2 on r.route_to = s2.Station_ID
where Route_ID = 1;

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我想你想要更像这样的东西：

SELECT
    Route.Route_ID,
    fromStation.Name,
    toStation.Name
FROM
    Route
    LEFT JOIN Stations AS fromStation
        ON Route.Route_From =fromStation.Station_ID
    LEFT JOIN Stations AS toStation
        ON Route.Route_To  =toStation.Station_ID
WHERE 
    Route.Route_ID = 1;

select s1.name as route_from, s2.name as route_to from route r
left join stations s1 on r.route_from = s1.Station_ID
left join stations s2 on r.route_to = s2.Station_ID
where Route_ID = 1;

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你说的两个站的值是什么意思