Mysql 如何选择某些'；id'；并对结果进行分组

在此查询中，我尝试选择用户已支付的款项总额：

SELECT *
from (select IFnull(t.diapason,'total') as diapason,
t.total_amount as total_amount 

FROM 
(SELECT p.user_id, p.amount as total_amount, CASE
when amount<=100 then '0-100'
when amount>100 then '100...' END AS diapason
FROM (SELECT distinct payments.user_id, SUM(amount) AS amount 
FROM payments inner JOIN (SELECT DISTINCT user_id FROM payments where 
     payment_time between '2000-01-01' and '2001-01-01') a ON 
payments.user_id = a.user_id 
GROUP BY payments.user_id) p) t  
GROUP BY diapason WITH ROLLUP) as t1  
ORDER BY total_amount desc;

通常，由每个用户曾经支付的总金额组成的组。例如，如果他支付了50美元，他属于“0-100”组。如果他支付了500-他在“100…”组中，但现在我需要知道每个组中用户支付的金额

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如果你愿意帮忙，谢谢你

我想您需要一个

SUM

或

AVG

：

SELECT user_id,
       SUM(Amount) `sum`,
       AVG(Amount) `avg`
FROM payments 
WHERE payment_time BETWEEN '2000-01-01' AND '2001-01-01'
GROUP BY ser_id

或者（2000-01-01和2001-01-01之间的

金额之和除以特定用户的记录总数）：

如果我理解正确，就不需要所有这些子查询。
简单的
sum
和
groupby
应该这样做：

SELECT t1.user_id, sum(t2.amount) as total, IF(sum(t2.amount)<=100, '0-100',  '100...') as grp 
FROM t1
INNER JOIN t2 on t1.user_id = t2.user_id
WHERE t2.payment_time between '2000-01-01' and '2001-01-01'
GROUP BY t1.user_id

选择t1.user\u id，sum（t2.amount）作为总计，如果（sum（t2.amount）这个查询有太多错误。你说的“组”是什么？@sskoko，我说的是由每个用户支付的总金额组成的组。例如，如果他支付了50美元，他在“0-100”组中。如果他支付了500美元，他在“100”组中但现在我需要知道每个组中用户支付的金额。
SELECT user_id,
       SUM(CASE WHEN payment_time BETWEEN '2000-01-01' AND '2001-01-01' THEN Amount ELSE 0 END) / COUNT(*) `customAvg`
FROM payments 
WHERE payment_time BETWEEN '2000-01-01' AND '2001-01-01'
GROUP BY ser_id

SELECT t1.user_id, sum(t2.amount) as total, IF(sum(t2.amount)<=100, '0-100',  '100...') as grp 
FROM t1
INNER JOIN t2 on t1.user_id = t2.user_id
WHERE t2.payment_time between '2000-01-01' and '2001-01-01'
GROUP BY t1.user_id