从MySQL获取每个人的最新记录

我有一张这样的桌子

╔════╦════════╦═════════════╦═════════════════╗
║ PK ║  NAME  ║   DEGREE    ║ YEAR_OF_PASSING ║
╠════╬════════╬═════════════╬═════════════════╣
║  1 ║ Shrey  ║ B.E.        ║            2004 ║
║  2 ║ Shrey  ║ High School ║            2000 ║
║  3 ║ Gaurav ║ B.E.        ║            2000 ║
║  4 ║ Gaurav ║ M.Sc.       ║            2002 ║
╚════╩════════╩═════════════╩═════════════════╝

如何查询以获得每个人的最新学位的结果集，如下所示

╔════╦════════╦════════╦═════════════════╗
║ PK ║  NAME  ║ DEGREE ║ YEAR_OF_PASSING ║
╠════╬════════╬════════╬═════════════════╣
║  1 ║ Shrey  ║ B.E.   ║            2004 ║
║  4 ║ Gaurav ║ M.Sc.  ║            2002 ║
╚════╩════════╩════════╩═════════════════╝

更新1

SELECT  a.*
FROM    tableName a
        INNER JOIN
        (
            SELECT  Name, MAX(Year_Of_Passing) max_val, MAX(PK) max_pk
            FROM tableName
            GROUP BY Name
        ) b ON  a.name = b.name AND
                CASE WHEN b.max_val IS NULL
                     THEN a.pk = max_PK
                     ELSE a.Year_Of_Passing = b.max_val 
                  END

---

非常感谢JW.，有些情况下，通过的年份=null，那么我可以拥有最高PK的记录吗？谢谢JW。我发现这个查询

选择PK、Name、Degree、MAX（通过的年）作为TableName组通过的年，按PK的名称顺序提供完全相同的输出。它们是等价的吗？@Shrey基本上不是。如果您尝试在任何其他服务器上运行该查询，该查询将生成一个错误。
SELECT  a.*
FROM    tableName a
        INNER JOIN
        (
            SELECT  Name, MAX(Year_Of_Passing) max_val, MAX(PK) max_pk
            FROM tableName
            GROUP BY Name
        ) b ON  a.name = b.name AND
                CASE WHEN b.max_val IS NULL
                     THEN a.pk = max_PK
                     ELSE a.Year_Of_Passing = b.max_val 
                  END