我用MySQL得到了空结果
我已经尝试在MySQL中显示整个表数据。行为(用户名、姓氏和部门)。刷新页面时没有结果我用MySQL得到了空结果,mysql,Mysql,我已经尝试在MySQL中显示整个表数据。行为(用户名、姓氏和部门)。刷新页面时没有结果 <?php $servername = "fdb19.awardspace.net"; $username = "2598428_db"; $password = "password"; $dbname = "2598428_db"; $conn = new mysqli($servername, $username, $password, $dbname); if ($conn->conne
<?php
$servername = "fdb19.awardspace.net";
$username = "2598428_db";
$password = "password";
$dbname = "2598428_db";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql="SELECT * From users";
$result = $conn->query($sql);
while($res = mysqli_fetch_array( $result )) {
echo $res['AverageSatisfactionScore'];
}
?>
您的回音是错误的
您需要显示有效的列名,如:
echo$res['id']
或echo$res['dept']
只需打印您的结果集的总计数即可
echo mysqli\u num\u行($result)代码>
它将打印结果中的记录总数
也可以尝试按顺序打印整行
print\r($res)代码>
不用
echo$res['AverageSatisfactionScore']代码>。