MySQL子查询分组依据

我有一个查询，它根据一个人的id（athleteid）显示比赛结果列表。我已经查询了数据库，以便它按照时间（性能）和事件（eventid）的顺序列出该人的种族，但我正在努力将其设置为子查询，以便我可以在之后对结果进行分组，以便为每个eventid提供最快的性能。这就是我到目前为止所做的：

$id = $_GET['id'];
$query = sprintf("SELECT events.eventcode, meetings.meetingid, meetings.meetingname, meetings.location, meetings.meetingdate, DATE_FORMAT(meetings.meetingdate,'%%d %%b %%Y') AS date, results.performance, results.unit, results.wind, agegroups.agegroup
FROM results 
JOIN athletes ON athletes.athleteid = results.athleteid
JOIN meetings ON meetings.meetingid = results.meetingid
JOIN events ON events.eventid = results.eventid
JOIN agegroups ON agegroups.agegroupid = results.agegroupid
WHERE results.athleteid='$id' AND events.eventtype = 'track' ORDER BY results.eventid asc, results.performance asc, meetings.meetingdate desc");

这可以正常工作，并以正确的顺序显示所有相关条目。然后我尝试将其转换为子查询，以便使用GROUPBY，但没有成功。这正是我想要做的：

$id = $_GET['id'];
$query = sprintf("SELECT * FROM (SELECT events.eventcode, meetings.meetingid, meetings.meetingname, meetings.location, meetings.meetingdate, DATE_FORMAT(meetings.meetingdate,'%%d %%b %%Y') AS date, results.performance, results.unit, results.wind, agegroups.agegroup
FROM results 
JOIN athletes ON athletes.athleteid = results.athleteid
JOIN meetings ON meetings.meetingid = results.meetingid
JOIN events ON events.eventid = results.eventid
JOIN agegroups ON agegroups.agegroupid = results.agegroupid
WHERE results.athleteid='$id' AND events.eventtype = 'track' ORDER BY results.eventid asc, results.performance asc, meetings.meetingdate desc) AS t1
GROUP BY t1.eventid");

但是，这给了我一个错误，它指出：“group语句”中的未知列“t1.eventid”

---

如果您没有在子查询中选择

eventid

，我们将非常感谢您的帮助。如果它不在那里，你怎么能分组呢

SELECT events.eventid,events.eventcode, 
meetings.meetingid, meetings.meetingname, 
meetings.location, meetings.meetingdate, 
DATE_FORMAT(meetings.meetingdate,'%%d %%b %%Y') AS date, 
results.performance, results.unit, results.wind, 
agegroups.agegroup
.......

---

这是因为子查询中没有该列，请尝试在子查询中添加该列，然后选择：

$id = $_GET['id'];
$query = sprintf("SELECT * FROM (SELECT events.eventid, events.eventcode, meetings.meetingid, meetings.meetingname, meetings.location, meetings.meetingdate, DATE_FORMAT(meetings.meetingdate,'%%d %%b %%Y') AS date, results.performance, results.unit, results.wind, agegroups.agegroup
FROM results 
JOIN athletes ON athletes.athleteid = results.athleteid
JOIN meetings ON meetings.meetingid = results.meetingid
JOIN events ON events.eventid = results.eventid
JOIN agegroups ON agegroups.agegroupid = results.agegroupid
WHERE results.athleteid='$id' AND events.eventtype = 'track' ORDER BY results.eventid asc, results.performance asc, meetings.meetingdate desc) AS t1
GROUP BY t1.eventid");

---

您好，如果您在mysql中使用

分组依据

，则

分组依据

中的

字段名

必须位于

所选列

。使用

Select*，t1.eventid from（Select..

。谢谢