MySQL求和、加入和分组方式。。。适当结构

MySQL求和、加入和分组方式。。。适当结构,mysql,sql,laravel,laravel-4,Mysql,Sql,Laravel,Laravel 4,我在浏览表和使用Laravel 4 Fluent将SQL语句按团队id分组时遇到了一些问题。如果我通过删除组,我将获得每个用户的总步骤。但我需要的是每个团队的总步骤 SQL语句: 不带分组依据的输出: 期望输出: 您应该在单个查询中使用GROUPBY,而不是以嵌套方式进行嵌套。 这里有一种方法: SELECT `user_challenge`.`team_id` , `teams`.`name` , SUM(`userStepSum`) as `TeamStepSum` FROM `use

我在浏览表和使用Laravel 4 Fluent将SQL语句按团队id分组时遇到了一些问题。如果我通过删除组,我将获得每个用户的总步骤。但我需要的是每个团队的总步骤

SQL语句:

不带分组依据的输出:

期望输出:


您应该在单个查询中使用GROUPBY,而不是以嵌套方式进行嵌套。 这里有一种方法:

SELECT  `user_challenge`.`team_id` ,  `teams`.`name` , SUM(`userStepSum`) as `TeamStepSum`
FROM  `user_challenge` 
INNER JOIN  `users` ON  `user_challenge`.`user_id` =  `users`.`id` 
INNER JOIN  `teams` ON  `user_challenge`.`team_id` =  `teams`.`id` 
INNER JOIN 
(
SELECT activities.user_id, SUM( activities.steps ) as `userStepSum`
FROM activities
where 
AND activities.created_at <=  '2013-11-30 15:32:45'
AND activities.date >=  '2013-10-01 15:32:45'
AND activities.date <=  '2013-11-30 15:32:45'
GROUP BY `activities`.`user_id`
) `user_steps` on `user_steps`.`user_id` = `user_challenge`.`user_id`
WHERE  `user_challenge`.`challenge_id` =2
AND  `user_challenge`.`team_id` IS NOT NULL 
GROUP BY  `user_challenge`.`team_id`

你也可以直接参加活动。祝你好运。

如果你不需要laravel fluent特定的解决方案,你不需要问题中包含的laravel标签。。。
$subquery = "(SELECT SUM(activities.$type) FROM activities WHERE activities.user_id = users.id AND activities.created_at <= '". $challenge->end_date ."' AND activities.date >= '". $challenge->start_date ."' AND activities.date <= '". $challenge->end_date ."') as $type";
$teams = DB::table('user_challenge')
    ->where('user_challenge.challenge_id', $challenge->id)
    ->whereNotNull('user_challenge.team_id')
    ->join('users','user_challenge.user_id','=','users.id')
    ->join('teams','user_challenge.team_id','=','teams.id')
    ->select('user_challenge.team_id', 'teams.name',DB::raw($subquery))
    ->groupBy('user_challenge.team_id')
    ->get();
team_id, name, steps
1, Team 1, null
team_id, name, steps
1, Team 1, null
1, Team 1, 13000
1, Team 1, 10000
team_id, name, steps
1, Team 1, 23000
SELECT  `user_challenge`.`team_id` ,  `teams`.`name` , SUM(`userStepSum`) as `TeamStepSum`
FROM  `user_challenge` 
INNER JOIN  `users` ON  `user_challenge`.`user_id` =  `users`.`id` 
INNER JOIN  `teams` ON  `user_challenge`.`team_id` =  `teams`.`id` 
INNER JOIN 
(
SELECT activities.user_id, SUM( activities.steps ) as `userStepSum`
FROM activities
where 
AND activities.created_at <=  '2013-11-30 15:32:45'
AND activities.date >=  '2013-10-01 15:32:45'
AND activities.date <=  '2013-11-30 15:32:45'
GROUP BY `activities`.`user_id`
) `user_steps` on `user_steps`.`user_id` = `user_challenge`.`user_id`
WHERE  `user_challenge`.`challenge_id` =2
AND  `user_challenge`.`team_id` IS NOT NULL 
GROUP BY  `user_challenge`.`team_id`