选择除distinct mysql之外的所有值

我是mysql的新手我很难准备一个查询，该查询将返回所有剩余的项目，即不同的项目 例如：

表名：

城市

字段为：

id、姓名、人口

我想得到所有不清晰的城市名称 我尝试过这样的事情，但它给了我一个错误

SELECT S.CITY FROM STATION AS S LEFT JOIN STATION ON (SELECT DISTINCT(P.CITY) FROM STATION AS P)

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有人能给我介绍一下吗

SELECT city, COUNT(city) AS count
FROM station
GROUP BY city
HAVING COUNT(city) > 1

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distinct不是一个函数，而是一个子句
如果您想使用distinct，您可以尝试在不匹配的地方使用子查询left jont

SELECT S.CITY 
FROM STATION AS S 
LEFT JOIN STATION ON ( 
    SELECT DISTINCT CITY 
     FROM STATION 
) T  S.CITY  = T.CITY 
where t.city is null 

但按城市和javing count（*）划分的aso组=1

SELECT CITY 
FROM STATION 
GROUP BY city
having count(*) = 1