Mysql 将两个Select语句合并为一个语句

我使用的是MySql 8.0.23，有两条select语句。第一条是这样写的：

SELECT w.userid,w.reportdate, t.teamname, sum(w.worked)/60 as Worked FROM apticproject.view_workedtime as w
inner join user u on u.userid=w.userid
left outer join teammembers m on m.member=w.userid
left outer join teams t on t.teamid=m.team
where reportdate >= '2021-03-01' and reportdate <'2021-04-01'
group by w.userid
order by fullname ;

SELECT r.userid, sum(r.invoicetime)/60 as invoicetime FROM apticproject.view_registeredtime as r
inner join user u on u.userid=r.userid 
left join teammembers m on m.member=r.userid
left join teams t on t.teamid=m.team
where fromdate >= '2021-03-01' and fromdate <'2021-04-01' and r.invoiced=1 and r.approved=1 and charge_customer=1 and r.zeroinvoice=0 
group by userid
order by fullname;

并给出以下输出：

第二条select语句如下所示：

SELECT w.userid,w.reportdate, t.teamname, sum(w.worked)/60 as Worked FROM apticproject.view_workedtime as w
inner join user u on u.userid=w.userid
left outer join teammembers m on m.member=w.userid
left outer join teams t on t.teamid=m.team
where reportdate >= '2021-03-01' and reportdate <'2021-04-01'
group by w.userid
order by fullname ;

SELECT r.userid, sum(r.invoicetime)/60 as invoicetime FROM apticproject.view_registeredtime as r
inner join user u on u.userid=r.userid 
left join teammembers m on m.member=r.userid
left join teams t on t.teamid=m.team
where fromdate >= '2021-03-01' and fromdate <'2021-04-01' and r.invoiced=1 and r.approved=1 and charge_customer=1 and r.zeroinvoice=0 
group by userid
order by fullname;

并给出以下输出：

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我希望能够将invoicetime列从第二条select语句连接到第一条select语句，以便invoicetime列显示在第一条select语句中的Worked列之后。正如您所看到的，我有一个可以用作连接点的userid。最有效的方法是什么？非常感谢您的帮助。

我设法找到了如下所示的解决方案。在MySQL中，您没有完全联接，只有Union存在，这是我使用的语法：

select x.userid, x.username, x.fullname,x.reportdate, x.teamname, x.Worked,y.invoicetime
from
(SELECT w.userid, u.username, u.fullname,w.reportdate, t.teamname, sum(w.worked)/60 as Worked FROM apticproject.view_workedtime as w
inner join user u on u.userid=w.userid
left outer join teammembers m on m.member=w.userid
left outer join teams t on t.teamid=m.team
where reportdate >= '2021-03-01' and reportdate <'2021-04-01'
group by w.userid) as x

left join

(SELECT r.userid, sum(r.invoicetime)/60 as invoicetime FROM apticproject.view_registeredtime as r
inner join user u on u.userid=r.userid 
left join teammembers m on m.member=r.userid
left join teams t on t.teamid=m.team
where fromdate >= '2021-03-01' and fromdate <'2021-04-01' and r.invoiced=1 and r.approved=1 and charge_customer=1 and r.zeroinvoice=0 
group by userid) as y on y.userid=x.userid

Union

select x.userid, x.username, x.fullname,x.reportdate, x.teamname, x.Worked,y.invoicetime
from
(SELECT w.userid, u.username, u.fullname,w.reportdate, t.teamname, sum(w.worked)/60 as Worked FROM apticproject.view_workedtime as w
inner join user u on u.userid=w.userid
left outer join teammembers m on m.member=w.userid
left outer join teams t on t.teamid=m.team
where reportdate >= '2021-03-01' and reportdate <'2021-04-01'
group by w.userid) as x

right join

(SELECT r.userid, sum(r.invoicetime)/60 as invoicetime FROM apticproject.view_registeredtime as r
inner join user u on u.userid=r.userid 
left join teammembers m on m.member=r.userid
left join teams t on t.teamid=m.team
where fromdate >= '2021-03-01' and fromdate <'2021-04-01' and r.invoiced=1 and r.approved=1 and charge_customer=1 and r.zeroinvoice=0 
group by userid) as y on y.userid=x.userid
order by fullname; 

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如果您不想看到第二个查询中的项目在第一个查询中没有用户记录，您可以在Darko86答案的后半部分删除union和全称join。

将您的查询用作子查询，按公共列join。请您的问题提及您使用的MySQL/MariaDB版本。使用v8+这些查询更容易编写，因为它们有.@O.Jones，它已更新