在MYSQL中返回所有结果以及有限/偏移结果的最有效方法

下面的查询从我的表中获取所有有限的结果集。然而，我有一个表过滤器，它要求所有的结果都存在，以提供一个完整的选择范围。是否有一种方法可以组合查询，以便它获取所有结果以及有限/偏移结果

"SELECT phone_deal_phone_allocations.*, 
                            phone_deal_phone_allocations.id as allocation_id,
                            phone_reseller_monthly_deals.*, 
                            phone_reseller_monthly_deals.id as deal_id, 
                            phone_variations.*,
                            phone_variations.id as variation_id, 
                            phone_colours.*, 
                            phone_colours.id as colour_id, 
                            phone_sizes.*,
                            phone_sizes.id as size_id,
                            phone_networks.*,
                            phone_networks.id as network_id 
                        FROM 
                        phone_deal_phone_allocations
                        JOIN phone_reseller_monthly_deals ON phone_reseller_monthly_deals.id=phone_deal_phone_allocations.deal_id 
                        JOIN phone_variations ON phone_variations.id=phone_deal_phone_allocations.phone_variations_id
                        JOIN phone_colours ON phone_colours.id=phone_variations.phone_colour_id
                        JOIN phone_sizes ON phone_sizes.id=phone_variations.phone_size_id
                        JOIN phone_networks ON phone_networks.id=phone_reseller_monthly_deals.phone_networks_id
                        ".$where."
                        AND phone_colours.phone_colour_name = 'Gold'
                        ORDER BY phone_sizes.phone_size_mb ASC 
                        LIMIT 0, 4"

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使用cte。全选union all select with limit。那么，您想要所有结果还是只想要一个子集？如果结果集sin

LIMIT

的总大小相当小，也许您可以缓存它，然后在UI上分页。使其易于帮助您：。