Mysql 分组前N行，但也需要对列值求和

我正在使用以下查询对数据集中前N行进行分组：

SELECT mgap_ska_id,mgap_ska_id_name, account_manager_id, 
mgap_growth AS growth,mgap_recovery,
(mgap_growth+mgap_recovery) total
  FROM
  (SELECT mgap_ska_id,mgap_ska_id_name, account_manager_id, mgap_growth,
  mgap_recovery,(mgap_growth+mgap_recovery) total,
    @acid_rank := IF(@current_acid = account_manager_id, @acid_rank + 1, 1) 
    AS acid_rank,
       @current_acid := account_manager_id 
       FROM mgap_orders
       ORDER BY account_manager_id, mgap_growth DESC 
     ) ranked
     WHERE acid_rank <= 5 

结果非常接近我需要的，但我有一个总的问题需要帮助。我已经缓存了一个查询结果的屏幕截图，为了隐私，我不得不屏蔽客户姓名和ID；mgap_ska_id和account_manager_id是INT列，mgap_ska_id_名称是VARCHAR

理论上我需要求和，我知道这是一个集合；这就是在保持排名得体的同时，多重mgap_增长值的问题

如果我分组，那么我将失去前5名。目前，mgap_增长值仅为mgap_增长列中每个mgap_ska_id的一个值；我需要它是每个mgap_ska_id的所有mgap_增长值的总和，并保持前五名，如图所示

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谢谢

您可以在选择字段中添加以下行：

(SELECT SUM(t.mgap_growth) FROM mgap_orders t WHERE t.mgap_ska_id = ranked.mgap_ska_id ) AS total_mgap_growth

因此，您的代码将是：

SELECT mgap_ska_id,mgap_ska_id_name, account_manager_id, 
mgap_growth AS growth,mgap_recovery,
(mgap_growth+mgap_recovery) total,
(SELECT SUM(t.mgap_growth) FROM mgap_orders t WHERE t.mgap_ska_id = ranked.mgap_ska_id ) AS total_mgap_growth
  FROM
  (SELECT mgap_ska_id,mgap_ska_id_name, account_manager_id, mgap_growth,
  mgap_recovery,(mgap_growth+mgap_recovery) total,
    @acid_rank := IF(@current_acid = account_manager_id, @acid_rank + 1, 1) 
    AS acid_rank,
       @current_acid := account_manager_id 
       FROM mgap_orders
       ORDER BY account_manager_id, mgap_growth DESC 
     ) ranked
     WHERE acid_rank <= 5 

如果帐户管理器id是自动生成的，它实际上不会告诉我们任何与隐私相关的信息。你希望结果是什么样的？这也将有助于样本起始数据的正确匿名化。