按周（7天）分组查询结果-MySql

我有一个查询，输出（排序）从2017年3月3日至今每天的日期和计数。有没有办法按周（7天）分组

query.sql：

SELECT SUM(a.ctr)
,a.datecreated
FROM 
(
    SELECT COUNT(*) as ctr, date_format(created, '%d/%m/%y ') as datecreated 
    FROM mimesi_indexer.meta_served_clips
    GROUP BY date(datecreated)
    UNION ALL 
    select 0 as ctr, date_format(selected_date,  '%d/%m/%y ') as datecreated 
       from 
     (select adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
    where selected_date 
    between (SELECT MIN(created) FROM mimesi_indexer.meta_served_clips)
        and (SELECT MAX(created) FROM mimesi_indexer.meta_served_clips)
) a
group by date(a.datecreated)
order by month(a.datecreated), date(a.datecreated)

结果（部分）：

通缉结果：

'3485',  '03/03/17'
'7716',  '10/03/17'

编辑：使用每周分组（a.datecreated）的结果：

p.S: 如果一周（7天）可以从2017年3月5日（2017年3月5日）开始，这将是完美的，因为这是一个星期一，第3天和第4天将保留为单个数字

SELECT SUM(a.ctr)
,a.datecreated
FROM 
(
    SELECT COUNT(*) as ctr, date_format(created, '%d/%m/%y ') as datecreated 
    FROM mimesi_indexer.meta_served_clips
    GROUP BY date(datecreated)
    UNION ALL 
    select 0 as ctr, date_format(selected_date,  '%d/%m/%y ') as datecreated 
       from 
     (select adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
    where selected_date 
    between (SELECT MIN(created) FROM mimesi_indexer.meta_served_clips)
        and (SELECT MAX(created) FROM mimesi_indexer.meta_served_clips)
) a
group by week(STR_TO_DATE(a.datecreated,'%d/%m/%y'))
order by month(a.datecreated), date(a.datecreated)

使用此行

按周分组（STR_TO_DATE（a.datecreated，'%d/%m/%y'））

您正在将字符串字段转换为日期，然后将该日期转换为星期

您可以尝试上述查询。

应使用：

GROUP BY WEEK(a.datecreated, 7)

---

或者查看第二个参数的值。

已经尝试过此方法，但不起作用。结果（所有结果）：

'38657'，'03/03/17''4773'，'07/03/17''28529'，'01/04/17''14191'，'05/04/17''34223'，'01/05/17''43093'，'04/05/17''82515'，'01/06/17''1804'，'12/06/17''23513'，'01/07/17''9287'，'05/07/17'

您没有尝试按周使用

分组（stru-TO-u-u-DATE创建日期（a.DATE s），%d/%m/%y）

只要尝试一次，你就会得到你想要的准确结果。请看：你的意思是什么？@草莓请帮助我，而不是仅仅链接东西当我使用一个词时，它的意思就是我选择它的意思-不多也不少。在本例中，在提供的链接上接受的答案说明了我想说的一切。@strybride You downvoter？？

SELECT SUM(a.ctr)
,a.datecreated
FROM 
(
    SELECT COUNT(*) as ctr, date_format(created, '%d/%m/%y ') as datecreated 
    FROM mimesi_indexer.meta_served_clips
    GROUP BY date(datecreated)
    UNION ALL 
    select 0 as ctr, date_format(selected_date,  '%d/%m/%y ') as datecreated 
       from 
     (select adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
    where selected_date 
    between (SELECT MIN(created) FROM mimesi_indexer.meta_served_clips)
        and (SELECT MAX(created) FROM mimesi_indexer.meta_served_clips)
) a
group by week(STR_TO_DATE(a.datecreated,'%d/%m/%y'))
order by month(a.datecreated), date(a.datecreated)

GROUP BY WEEK(a.datecreated, 7)