MySQL联合声明

我只想问一下如何将两个查询和 区别在于where语句。一个是带有

的，其中c.transac_type=0

，另一个是

的，其中c.transac_type=1“

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我想在c.transac_type=0和c.transac_type=1的条件下看到SUM（c.amount）的输出，因为它们有不同的SUM（c.amount）输出

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联合它将相当简单，但不确定它是否会给您提供有用的值

SELECT a.id, a.branch_code, SUM(c.amount) AS AmountSum, d.category, e.branch_commission 
FROM control_panel_client_create AS a
    RIGHT JOIN sales_add_h AS b ON a.id = b.branch_code_id 
    RIGHT JOIN sales_add_i AS c ON b.id = c.sales_h_id 
    RIGHT JOIN control_panel_item_create AS d ON c.item_code_id = d.id
    INNER JOIN control_panel_client_create AS e ON b.branch_code_id = e.id
    WHERE c.transac_type = 0 
GROUP BY d.category, b.branch_code_id 
UNION
SELECT a.id, a.branch_code, SUM(c.amount) AS AmountSum, d.category, e.branch_commission 
FROM control_panel_client_create AS a
    RIGHT JOIN sales_add_h AS b ON a.id = b.branch_code_id 
    RIGHT JOIN sales_add_i AS c ON b.id = c.sales_h_id 
    RIGHT JOIN control_panel_item_create AS d ON c.item_code_id = d.id
    INNER JOIN control_panel_client_create AS e ON b.branch_code_id = e.id
    WHERE c.transac_type = 1 
GROUP BY d.category, b.branch_code_id 
ORDER BY AmountSum DESC

你可以得到两种transac类型的总和

SELECT a.id, a.branch_code, SUM(c.amount) AS AmountSum, d.category, e.branch_commission 
FROM control_panel_client_create AS a
    RIGHT JOIN sales_add_h AS b ON a.id = b.branch_code_id 
    RIGHT JOIN sales_add_i AS c ON b.id = c.sales_h_id 
    RIGHT JOIN control_panel_item_create AS d ON c.item_code_id = d.id
    INNER JOIN control_panel_client_create AS e ON b.branch_code_id = e.id
    WHERE c.transac_type IN (0, 1) 
GROUP BY d.category, b.branch_code_id 
ORDER BY AmountSum DESC

或者分别计算两者的总和

SELECT a.id, a.branch_code, SUM(c.amount) AS AmountSum, d.category, e.branch_commission , c.transac_type
FROM control_panel_client_create AS a
    RIGHT JOIN sales_add_h AS b ON a.id = b.branch_code_id 
    RIGHT JOIN sales_add_i AS c ON b.id = c.sales_h_id 
    RIGHT JOIN control_panel_item_create AS d ON c.item_code_id = d.id
    INNER JOIN control_panel_client_create AS e ON b.branch_code_id = e.id
    WHERE c.transac_type IN (0, 1) 
GROUP BY d.category, b.branch_code_id, c.transac_type
ORDER BY AmountSum DESC

将两个计数放在同一行的糟糕方式：-

SELECT a.id, a.branch_code, SUM(IF(c.transac_type=0,c.amount, 0)) AS AmountSumTransac_0, SUM(IF(c.transac_type=1, c.amount, 0)) AS AmountSumTransac_1, d.category, e.branch_commission 
FROM control_panel_client_create AS a
    RIGHT JOIN sales_add_h AS b ON a.id = b.branch_code_id 
    RIGHT JOIN sales_add_i AS c ON b.id = c.sales_h_id 
    RIGHT JOIN control_panel_item_create AS d ON c.item_code_id = d.id
    INNER JOIN control_panel_client_create AS e ON b.branch_code_id = e.id
    WHERE c.transac_type IN (0, 1) 
GROUP BY d.category, b.branch_code_id
ORDER BY AmountSum DESC

您可以在（0,1）中使用

，而不是联合

试试这个

    SELECT a.id, a.branch_code, SUM(c.amount), d.category, e.branch_commission 
FROM control_panel_client_create AS a
RIGHT JOIN sales_add_h AS b ON a.id = b.branch_code_id 
RIGHT JOIN sales_add_i AS c ON b.id = c.sales_h_id 
RIGHT JOIN control_panel_item_create AS d ON c.item_code_id = d.id
INNER JOIN control_panel_client_create AS e ON b.branch_code_id = e.id
WHERE c.transac_type IN (0, 1)
GROUP BY d.category, b.branch_code_id,c.transac_type  ORDER BY SUM(c.amount) DESC

如果要在两个不同的列中计算事务类型的总和，则需要使用条件聚合：

SELECT a.id, a.branch_code, SUM(c.amount) as totAmount,
       sum(case when c.transac_type = 0 then c.amount end) as Trans0_Amount,
       sum(case when c.transac_type = 1 then c.amount end) as Trans1_Amount,
       d.category, e.branch_commission 
FROM control_panel_client_create AS a
RIGHT JOIN sales_add_h AS b ON a.id = b.branch_code_id 
RIGHT JOIN sales_add_i AS c ON b.id = c.sales_h_id 
RIGHT JOIN control_panel_item_create AS d ON c.item_code_id = d.id
INNER JOIN control_panel_client_create AS e ON b.branch_code_id = e.id
WHERE c.transac_type IN (0, 1)
GROUP BY d.category, b.branch_code_id
ORDER BY SUM(c.amount) DESC

为什么不
c.transac_键入（0，1）
而不是
UNION
？mysqli在这里是一个错误的标签仅供参考，“[mysql]和“right join”这两个术语目前出现了952次。与之相比，“[mysql]和“left join”出现了22935次……我只是说。我想看看SUM（c.amount）的输出在c.transac_type=0和c.transac_type=1的情况下，因为它们的总和（c.amount）输出不同，然后通过检查我的更新答案在组中添加
c.transac_type
，我是否可以将c.transac_type=0的总和（c.amount）列和另一个总和（c.amount）列分开对于c.transac_type=1的情况，它将按c.transac_type分组，然后它将是每个类型的不同总和。如果您没有得到结果，请将
c.transac_type
移动到组中的第一位by我想查看总和（c.amount）的输出在c.transac_type=0和c.transac_type=1的情况下，因为它们的SUM（c.amount）输出不同——最后一个查询应该这样做（将c.transac_type添加到GROUP BY中，并将其检查改为in）。是否可以为SUM（c.amount）分隔一列对于c.transac_type=0，对于c.transac_type=1，另一列是SUM（c.amount）。这可能会以一种糟糕的方式完成（将添加代码来回答这个问题）OMG！这正是我需要的。感谢您的帮助。已经在使用它了：）并且工作非常完美：）
SELECT a.id, a.branch_code, SUM(c.amount) as totAmount,
       sum(case when c.transac_type = 0 then c.amount end) as Trans0_Amount,
       sum(case when c.transac_type = 1 then c.amount end) as Trans1_Amount,
       d.category, e.branch_commission 
FROM control_panel_client_create AS a
RIGHT JOIN sales_add_h AS b ON a.id = b.branch_code_id 
RIGHT JOIN sales_add_i AS c ON b.id = c.sales_h_id 
RIGHT JOIN control_panel_item_create AS d ON c.item_code_id = d.id
INNER JOIN control_panel_client_create AS e ON b.branch_code_id = e.id
WHERE c.transac_type IN (0, 1)
GROUP BY d.category, b.branch_code_id
ORDER BY SUM(c.amount) DESC