在多个列中搜索MySQL并找到匹配的列
我需要一些关于如何做到这一点的建议。如果我有这样的疑问 从在多个列中搜索MySQL并找到匹配的列,mysql,Mysql,我需要一些关于如何做到这一点的建议。如果我有这样的疑问 从目录中选择*其中记录id=$var或表单id=$var 我想做的是知道哪列匹配。是记录还是表格?可能是这样的: select a,b,c, 1 from catalog where record_id = $var union select a,b,c, 2 from catalog where form_id = $var 然后1或2告诉你哪个是哪个。可能是这样的: select a,b,c, 1 from catalog where
目录
中选择*其中记录id
=$var或表单id
=$var
我想做的是知道哪列匹配。是记录还是表格?可能是这样的:
select a,b,c, 1 from catalog where record_id = $var
union
select a,b,c, 2 from catalog where form_id = $var
然后1或2告诉你哪个是哪个。可能是这样的:
select a,b,c, 1 from catalog where record_id = $var
union
select a,b,c, 2 from catalog where form_id = $var
SELECT *,
CASE
WHEN record_id = $var and form_id = $var THEN 'both'
WHEN record_id = $var THEN 'record_id'
WHEN form_id = $var THEN 'form_id'
ELSE 'none' -- can't happen becouse of where clause
END CASE as how_it_was
FROM catalog WHERE record_id = $var OR form_id = $var;
然后1或2告诉你哪个是哪个
SELECT *,
CASE
WHEN record_id = $var and form_id = $var THEN 'both'
WHEN record_id = $var THEN 'record_id'
WHEN form_id = $var THEN 'form_id'
ELSE 'none' -- can't happen becouse of where clause
END CASE as how_it_was
FROM catalog WHERE record_id = $var OR form_id = $var;
请注意$var上的sql injetion
select *,
case when record_id = $var then 1 else 2 end as matches
from table
where record_id = $var or form_id = $var
请注意$var上的sql injetion您想如何/在何处使用此信息?您想如何/在何处使用此信息?很抱歉我的无知。我对路易斯和你犯了同样的错误。我得到了一个错误。您的SQL语法有错误;检查与MySQL服务器版本对应的手册,以了解第5行“table where record_id=522或form_id=123”附近使用的正确语法;对不起我的无知。我对路易斯和你犯了同样的错误。我得到了一个错误。您的SQL语法有错误;检查与MySQL服务器版本对应的手册,以了解第5行“table where record_id=522或form_id=123”附近使用的正确语法;
select *,
case when record_id = $var then 1 else 2 end as matches
from table
where record_id = $var or form_id = $var