MySQL正在计算两个别名的百分比

我已经设法计算出我需要什么，现在我想知道我如何能够表示两个别名的百分比比率

SELECT c.fullname, COUNT( DISTINCT cc.userid ) AS  'calc1', COUNT( DISTINCT sst.id ) AS  'calc2'
FROM mdl_course c
INNER JOIN mdl_course_completions cc ON c.id = cc.course
INNER JOIN mdl_scorm s ON s.course = c.id
INNER JOIN mdl_scorm_scoes_track sst ON s.id = sst.scormid
INNER JOIN mdl_user u ON u.id = sst.userid
WHERE timecompleted IS NOT NULL 
AND sst.element =  'x.start.time'
GROUP BY c.fullname
ORDER BY  `calc2` DESC  

我尝试了

concat（round（（SELECT（'Calc1'）/SELECT（'Calc2'）*100），2），“%”作为百分比

但它不起作用

查询表示

fullname  calc1 calc2
Something1  29    92
Something2  16    81
Something3  30    75

您可以尝试以下查询：

您可以尝试以下查询：

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期望的结果是什么？calc1到Calc2的百分比表示你能在这里添加结果列吗？你检查过我们的ans吗？对不起，我失业了。我明天去查。谢谢：）期望的结果是什么？calc1到Calc2的百分比表示你能在这里添加结果栏吗？你检查过我们的ans吗？对不起，我失业了。我明天去查。谢谢：）开始时少了几个，但它起作用了！谢谢！开始时少了几个，但它起作用了！谢谢！

select fullname, calc1, calc2, (calc1*100/calc2) per_ration from
( SELECT c.fullname, COUNT( DISTINCT cc.userid ) AS  'calc1', COUNT( DISTINCT sst.id ) AS  'calc2'
FROM mdl_course c
INNER JOIN mdl_course_completions cc ON c.id = cc.course
INNER JOIN mdl_scorm s ON s.course = c.id
INNER JOIN mdl_scorm_scoes_track sst ON s.id = sst.scormid
INNER JOIN mdl_user u ON u.id = sst.userid
WHERE timecompleted IS NOT NULL 
AND sst.element =  'x.start.time'
GROUP BY c.fullname
ORDER BY  `calc2` DESC ) as temp_tab;

SELECT c.fullname, COUNT( DISTINCT cc.userid ) AS  'calc1', COUNT( DISTINCT sst.id ) AS  'calc2',
round(COUNT( DISTINCT cc.userid )/COUNT( DISTINCT sst.id ) )*100),2) as result
FROM mdl_course c
INNER JOIN mdl_course_completions cc ON c.id = cc.course
INNER JOIN mdl_scorm s ON s.course = c.id
INNER JOIN mdl_scorm_scoes_track sst ON s.id = sst.scormid
INNER JOIN mdl_user u ON u.id = sst.userid
WHERE timecompleted IS NOT NULL 
AND sst.element =  'x.start.time'
GROUP BY c.fullname
ORDER BY  `calc2` DESC