Mysql 需要以下场景的sql查询a

我想选择拥有尼泊尔人所有汽车的车主

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请帮我解决这个问题

你的意思是说你想让车主栏中的所有车都等于尼泊尔车吗？在一张桌子里

我希望，除非是更复杂的事情，否则您应该能够通过以下方式完成：

Car      Owner

'honda','nepolian'
'benz','nepolian'
'nissan','nepolian'
'lexus','sivaji'
'honda','sivaji'
'benz','sivaji'
'nissan','sivaji'
'landrover','kumar'
'kiamotors','kumar'
'honda','kumar'
'ferrari','vivek'
'suziki','vivek'

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不知道为什么要将其同时标记为mysql和oracle，但以下是如何在mysql中未经测试：

SELECT car
FROM *name of table*
WHERE owner = 'nepolian';

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也许对你有帮助！在mysql中执行就可以了！如果上面的sql是可行的，并且不是很慢，请给我一个消息

首先找出你正在使用的RDBMS。你想要什么还不清楚！尝试编辑您的问题并发布您的数据库模式！而且精确到你想要的！拥有尼泊尔人所有汽车的车主就是尼泊尔人！我想找到拥有nepolian所有汽车的车主。如果你对你的表名保密，这会使谈论和回答变得更加困难。请至少发布一些你尝试使用的SQL示例。堆栈溢出是为了帮助您，但不是从头开始编写代码：

select owner
from yourtable
where car in (select car from yourtable where owner='nepolian')
and owner <> 'nepolian'
group by owner
having group_concat(car order by car)=(select group_concat(car order by car) from yourtable where owner='nepolian');

having group_concat(distinct car order by car)=(select group_concat(distinct car order by car) from yourtable where owner='nepolian');

select t.owner from (
  select count(t1.car) as car_count, t1.owner from tableName t1
  join tableName t2 on t2.car = t1.car
  where t2.owner = 'nepolian' and t1.owner <> 'nepolian'
  group by t1.owner )
t where t.car_count = (
  select tmp.car_count from (
         select count(car) as car_count, owner from tableName
         where owner = 'nepolian' group by owner
  ) tmp
)