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尝试检查bash脚本中是否存在Mysql用户_Mysql_Bash - Fatal编程技术网

尝试检查bash脚本中是否存在Mysql用户

尝试检查bash脚本中是否存在Mysql用户,mysql,bash,Mysql,Bash,我试图检查是否存在MYSQL用户。这是我所能做到的。我无法从输出中获取答案 #!/bin/bash echo -e "What is the MYSQL username called" read DBUSER if [ -z "$DBUSER" ] then exit mysql -uUSER -pPASS -e "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')";

我试图检查是否存在MYSQL用户。这是我所能做到的。我无法从输出中获取答案

 #!/bin/bash
echo -e "What is the MYSQL username called"
    read DBUSER
    if [ -z "$DBUSER" ]
    then
    exit

    mysql -uUSER -pPASS -e "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')";

    if 
    yes
    do this
    else
    do this
这是我得到的输出

+-----------------------------------------------------+
| EXISTS(SELECT 1 FROM mysql.user WHERE user = 'bob') |
+-----------------------------------------------------+
|                                                   1 |
+-----------------------------------------------------+

请任何人帮忙

将结果分配给变量可以这样做:

RESULT_VARIABLE="$(mysql -uUSER -pPASS -se "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')")"
顺便说一句,您还可以在MySQL中为一列添加别名

SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER') AS does_it_exist

非常感谢你的帮助。这是工作的最终结果

它需要-sse

RESULT_VARIABLE="$(mysql -uUSER -pPASS -sse "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')")"

if [ "$RESULT_VARIABLE" = 1 ]; then
echo "TRUE"
else
  echo "FALSE"
fi

非常感谢。然后我试着去了解结果。如果[$RESULT_VARIABLE=1],这会给我一个错误;然后回显为真,否则回显重试,这很明显,但只是为了表示肯定。。。这对我使用shell\u exec->$is\u mysql\u user=shell\u exec'mysql-defaults extra file=MYPATHTOSTOREDCREDENTIALS-sse SELECT EXISTSSELECT 1 FROM mysql.user WHERE user=\$用户名。“\”;