Mysql 将子查询与id连接的子句分组时出现错误1054

获取此查询：

select 
T.id_empresa, max(periodo) as ultimoPeriodo, ( 
                        select sum(monto) from cuotasindical.pagos
                        where id_empresa = T.id_empresa and periodo = max(T.periodo)
                       ) as ultimoMonto, 
min(periodo) as periodoAnterior, (
                  select sum(monto) from cuotasindical.pagos
                  where id_empresa = T.id_empresa and periodo = min(T.periodo)
                   ) as anteriorMonto
from 
  (
    select 
    P1.id_empresa, P1.periodo, sum(monto) as monto
    from cuotasindical.pagos P1
    where P1.id_empresa in (select id_empresa from cuotasindical.empresa where id_delegacion = 5)
    group by P1.id_empresa, P1.periodo
    having P1.periodo in (
                select * from (
                                select periodo
                                from cuotasindical.pagos  
                                where P1.id_empresa = id_empresa order by periodo desc limit 2
                            ) as L
               )
    and count(distinct P1.periodo) > 1
  ) T
group by id_empresa
having (abs(max(monto) - min(monto))*100/
                    (
                      select sum(monto) from cuotasindical.pagos T2
                      where T2.id_empresa = id_empresa and T2.periodo = max(periodo)
                    ) > 10);

对于每个empresa，需要比较最后两个PAGO（由periodo订购），以查看其差异是否大于或小于某个百分比（在本例中为10）

我要走了

错误代码：1054。“where子句”中的未知列“P1.id\u empresa”

其中唯一具有该比较的where子句是具有limit的子查询

having P1.periodo in (
                select * from (
        select periodo
        from cuotasindical.pagos  
        where P1.id_empresa = id_empresa 
        order by periodo desc limit 2
        ) as L
               )
    and count(distinct P1.periodo) > 1

双重子查询用于避免in子句中的限制2（在链接上获取该限制）

为什么我会犯这样的错误？我想我可以在having子句中的子查询中加入group by之后（就像where子句一样）

或者是我遗漏了一个错误

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提前感谢

问题在于mysql在子查询中只有一个深层次的作用域

我还有子查询限制的问题，所以，我所做的是

    ..having P1.periodo in 
    (
       select max(periodo) as periodo
       from cuotasindical.pagos H
       where P1.id_empresa = id_empresa 
    ) OR
    P1.periodo in (
       select max(periodo) as periodo
       from cuotasindical.pagos H
       where P1.id_empresa = id_empresa and periodo != P1.periodo
    )
and count(distinct P1.periodo) > 1

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在specefic错误中，id_empresa实际上是cuotasindical.pagos中的一列吗

如果不是这样，我认为优化器可能会感到困惑，因为having子句包含了组中某个内容的信息，by。。。“在（）中具有P1.periodo”。P1.periodo也是一个group by

据我所知，GROUPBY用于非聚合字段。其中为非聚合字段

拥有是最奇怪的。。。“根据您已聚合的内容进行筛选”>您尚未聚合P1.periodo，但如果这是一个问题，则错误消息在某种程度上是决定性的

如果数据库支持它，我会考虑调试和可见性来查看CTE（公共表表达式）。（不确定最新的MySQL）

如果它不支持，请尝试使用视图。。。这里有相当多的代码都引用了相同的两个表。也许最好生成一个数据集，然后根据需要连接它。我认为这会使事后的过滤更容易

凝灰岩告诉没有实际连接到数据库，但可能是这样的东西。另外，我会给所有东西都加上别名，因为告诉什么列在什么表中是很困难的

with temp as ( 
/* Setup common table expression with basically all the info we need If your
 * DBMS doesn't support common table expressions (CTE's) then put this in a
 * view, or a temp table? */  
select 
    t1.id_empresa    as id_empresa    , 
    t1.periodo       as periodo       , 
    t2.id_delegacion as id_delegacion ,
    t2.monto         as monto
from 
    cuotasindical.pagos   as t1 inner join 
    cuotasindical.empresa as t2 on t1.id_empresa = t2.id_empresa and t2.id_delegacion = 5 
)
select 
    t1.id_empresa           as id_empresa   ,
    max(t1.ultimoPeriodo)   as ultimoPeriodo,
    min(t2.anteriorPeriodo) as anteriorPeriodo,
    sum(t3.ultimoMonto  )   as ultimoMonto , 
    sum(t4.anteriorMonto)   as anteriorMonto 
from 
    (select id_empresa, max(periodo)        as ultimoPeriodo   from temp) as t1 inner join 
    (select id_empresa, min(periodo)        as anteriorPeriodo from temp) as t2 on t1.id_empresa = t2.id_empresa inner join 
    (select id_empresa, periodo, sum(monto) as ultimoMonto     from temp) as t3 on t1.id_empresa = t3.id_empresa and t1.ultimoPeriodo = t3.periodo  inner join  
    (select id_empresa, periodo, sum(monto) as anteriorMonto   from temp) as t4 on t1.id_empresa = t4.id_empresa and t2.anteriorMonto = t4.periodo  inner join  
where 
    .....
group by 
    t1.id_empresa           
having 
    ..... 

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谢谢你的回答。。谷歌搜索发现的问题，是子查询中的级别范围问题；mysql只支持一个级别：(