使用mysql的组和

我有三张表：财务年度表、房屋明细表、消费者明细表。我需要按年度和子收入获得每个税务组的总和。我的表和查询位于此链接中：

获得结果：

Name  house_number  address  subincome   financial_year  gtax  htax  LTAX
--------------------------------------------------------------------------
Bala  22            Mumbai   Garbage tax 2015-2016       200   NULL  NULL
Bala  22            Mumbai   Garbage tax 2016-2017       250   NULL  NULL
Bala  22            Mumbai   House tax   2015-2016       NULL  0     NULL
Bala  22            Mumbai   House tax   2016-2017       NULL  145   NULL
Bala  22            Mumbai   Light tax   2015-2016       NULL  NULL  510
Bala  22            Mumbai   Light tax   2016-2017       NULL  NULL  200

Name    house_number    address    gtax    htax    LTAX
--------------------------------------------------------
Bala    22              Mumbai     450     145     710

预期结果：

Name  house_number  address  subincome   financial_year  gtax  htax  LTAX
--------------------------------------------------------------------------
Bala  22            Mumbai   Garbage tax 2015-2016       200   NULL  NULL
Bala  22            Mumbai   Garbage tax 2016-2017       250   NULL  NULL
Bala  22            Mumbai   House tax   2015-2016       NULL  0     NULL
Bala  22            Mumbai   House tax   2016-2017       NULL  145   NULL
Bala  22            Mumbai   Light tax   2015-2016       NULL  NULL  510
Bala  22            Mumbai   Light tax   2016-2017       NULL  NULL  200

Name    house_number    address    gtax    htax    LTAX
--------------------------------------------------------
Bala    22              Mumbai     450     145     710

---

试试这个，它会给出你想要的确切结果，我只是创建一个驱动表，然后求和

SELECT name
     , house_number
     , address
     , SUM(gtax) as gtax
     , SUM(htax) as htax
     , SUM(LTAX) LTAX
FROM (SELECT c.consumer_name as Name
           , c.house_number
           , c.address,h.subincome
           , h.financial_year
           , CASE WHEN h.subincome = 'Garbage tax' THEN f.garbage_tax - sum(h.rupees)END as gtax
           , CASE WHEN h.subincome = 'House tax' THEN f.house_tax - sum(h.rupees) END as htax
           , CASE WHEN h.subincome = 'Light tax' THEN f.light_tax - sum(h.rupees) END as LTAX
      FROM house_details h
          INNER JOIN financial_year f ON h.financial_year = f.year AND h.house_id = f.house_number
          INNER JOIN consumer_details c ON h.house_id = c.house_number AND h.financial_year != '2017-2018'
      GROUP BY h.subincome, h.financial_year) as main
GROUP BY house_number 

结果是：

---

您正在寻找有条件的汇总注意：只有在每个会计年度的每个subincometax类型内部详细信息都有条目的情况下，此解决方案才有效

SELECT c.consumer_name as Name, c.house_number, c.address,
sum(CASE WHEN h.subincome = 'Garbage tax' THEN f.garbage_tax else 0 end) - 
sum(CASE WHEN h.subincome = 'Garbage tax' THEN h.rupees else 0 END) as gtax, 
sum(CASE WHEN h.subincome = 'House tax' THEN f.house_tax else 0 end) -
sum(CASE WHEN h.subincome = 'House tax' THEN h.rupees else 0 END) as htax, 
sum(CASE WHEN h.subincome = 'Light tax' THEN f.light_tax else 0 end) - 
sum(CASE WHEN h.subincome = 'Light tax' THEN h.rupees else 0 END) as LTAX 
from house_details h 
INNER JOIN financial_year f ON h.financial_year = f.year AND h.house_id = f.house_number 
INNER JOIN consumer_details c ON h.house_id = c.house_number AND h.financial_year != '2017-2018' 
group by c.consumer_name , c.house_number, c.address

结果

+------+--------------+---------+------+------+------+
| Name | house_number | address | gtax | htax | LTAX |
+------+--------------+---------+------+------+------+
| Bala | 22           | Mumbai  |  450 |  145 |  710 |
+------+--------------+---------+------+------+------+
1 row in set (0.03 sec)

如果不能保证每个财政年度的每个子收入都有一个条目，那么解决方案就必须从应纳税表财政年度开始，在我看来，该表设计糟糕，缺乏灵活性，并强制采用次优解决方案

select c.consumer_name as Name, s.house_number, c.address,
        sum(case when subincome = 'garbage tax' then taxdue else 0 end) - sum(case when subincome = 'garbage tax' then taxpaid else 0 end) as gtax,
        sum(case when subincome = 'house tax' then taxdue else 0 end) - sum(case when subincome = 'house tax' then taxpaid else 0 end) as htax,
        sum(case when subincome = 'light tax' then taxdue else 0 end) - sum(case when subincome = 'light tax' then taxpaid else 0 end) as ltax
from 
(
SELECT  F.`house_number`, F.`year`, F.`house_tax` taxdue, F.`createdAt`, F.`updatedAt`,ifnull(h.subincome,'house_tax') subincome,ifnull(H.RUPEES,0) taxpaid
FROM FINANCIAL_YEARS F
LEFT  JOIN house_details H ON H.HOUSE_ID = F.HOUSE_NUMBER AND H.SUBINCOME = 'house tax' and f.year = h.financial_year
#where f.house_number = 22
union all
SELECT F.`house_number`, F.`year`, F.`light_tax`,  F.`createdAt`, F.`updatedAt`,ifnull(h.subincome,'light tax'),ifnull(H.RUPEES,0) 
FROM FINANCIAL_YEARS F
LEFT  JOIN house_details H ON H.HOUSE_ID = F.HOUSE_NUMBER AND H.SUBINCOME = 'light tax' and f.year = h.financial_year
#where f.house_number = 2
union all
SELECT F.`house_number`, F.`year`, F.`garbage_tax`, F.`createdAt`, F.`updatedAt`,ifnull(h.subincome,'garbage tax'),ifnull(H.RUPEES,0) 
FROM FINANCIAL_YEARS F
LEFT  JOIN house_details H ON H.HOUSE_ID = F.HOUSE_NUMBER AND H.SUBINCOME = 'garbage tax' and f.year = h.financial_year
#where f.house_number = 2
) s
join consumer_details c on s.house_number = c.house_number
where s.year <> '2017-2018'
group by c.consumer_name , s.house_number, c.address

---

将结果粘贴为文本，而不是图像。有些人看不到图片。链接是指向图片而不是sqlfiddle。@P.Salmon是的，我更新了，请检查。请检查更新的答案。顺便说一句，您可能想更改一些表名和列名，使其更有意义。请您解释一下taxdue字段的用途。在unionor union all语句中，提供的字段数必须相同，taxdue是您拥有的3种税种的别名，我几乎可以使用任何字符串代替taxdue。