Mysql 使用SQL、地理坐标和半径查询重叠区域
我有一个MySQL数据集,它由纬度、经度和一个值组成。我试图将其纬度和经度坐标在其他纬度和经度坐标的给定半径内的值相加(让我们称之为“焦点”)。最棘手的是,我试图从重叠区域中分离出不同的坐标-例如,半径1与半径2重叠的区域 有半径的每个焦点都有多个半径“区域”,因此对于任意给定的一组横向/纵向坐标,可以总结出很多东西。我成功地完成了一个查询,虽然有点慢,但基本上是有效的:Mysql 使用SQL、地理坐标和半径查询重叠区域,mysql,sql,query-optimization,Mysql,Sql,Query Optimization,我有一个MySQL数据集,它由纬度、经度和一个值组成。我试图将其纬度和经度坐标在其他纬度和经度坐标的给定半径内的值相加(让我们称之为“焦点”)。最棘手的是,我试图从重叠区域中分离出不同的坐标-例如,半径1与半径2重叠的区域 有半径的每个焦点都有多个半径“区域”,因此对于任意给定的一组横向/纵向坐标,可以总结出很多东西。我成功地完成了一个查询,虽然有点慢,但基本上是有效的: Select Sum(If(`zone`='z0_0x1_0',`value`,0)) a
Select
Sum(If(`zone`='z0_0x1_0',`value`,0)) as `z0_0x1_0`,
Sum(If(`zone`='z0_0x1_1',`value`,0)) as `z0_0x1_1`,
Sum(If(`zone`='z0_0x1_2',`value`,0)) as `z0_0x1_2`,
Sum(If(`zone`='z0_0x1_3',`value`,0)) as `z0_0x1_3`,
Sum(If(`zone`='z0_1x1_0',`value`,0)) as `z0_1x1_0`,
Sum(If(`zone`='z0_1x1_1',`value`,0)) as `z0_1x1_1`,
Sum(If(`zone`='z0_1x1_2',`value`,0)) as `z0_1x1_2`,
Sum(If(`zone`='z0_2x1_0',`value`,0)) as `z0_2x1_0`,
Sum(If(`zone`='z0_2x1_1',`value`,0)) as `z0_2x1_1`,
Sum(If(`zone`='z0_3x1_0',`value`,0)) as `z0_3x1_0`,
Sum(If(`zone`='z0_3x1_1',`value`,0)) as `z0_3x1_1`,
Sum(If(`zone`='z0_0',`value`,0)) as `z0_0`,
Sum(If(`zone`='z0_1',`value`,0)) as `z0_1`,
Sum(If(`zone`='z0_2',`value`,0)) as `z0_2`,
Sum(If(`zone`='z0_3',`value`,0)) as `z0_3`,
Sum(If(`zone`='z1_0',`value`,0)) as `z1_0`,
Sum(If(`zone`='z1_1',`value`,0)) as `z1_1`,
Sum(If(`zone`='z1_2',`value`,0)) as `z1_2`,
Sum(If(`zone`='z1_3',`value`,0)) as `z1_3`
From
(Select `lat`, `lng`, `value`,
Case
When ((`dist_0` Between 2.8723597844095 And 4.3343662110324) And (`dist_1` Between 3.6260179152491 And 5.4681062617155)) Then 'z0_0x1_0'
When ((`dist_0` Between 2.8723597844095 And 4.3343662110324) And (`dist_1` Between 2.1278369006061 And 3.6260179152491)) Then 'z0_0x1_1'
When ((`dist_0` Between 2.8723597844095 And 4.3343662110324) And (`dist_1` Between 1.3333495959677 And 2.1278369006061)) Then 'z0_0x1_2'
When ((`dist_0` Between 2.8723597844095 And 4.3343662110324) And (`dist_1` Between 0 And 1.3333495959677)) Then 'z0_0x1_3'
When ((`dist_0` Between 1.68658498678 And 2.8723597844095) And (`dist_1` Between 3.6260179152491 And 5.4681062617155)) Then 'z0_1x1_0'
When ((`dist_0` Between 1.68658498678 And 2.8723597844095) And (`dist_1` Between 2.1278369006061 And 3.6260179152491)) Then 'z0_1x1_1'
When ((`dist_0` Between 1.68658498678 And 2.8723597844095) And (`dist_1` Between 1.3333495959677 And 2.1278369006061)) Then 'z0_1x1_2'
When ((`dist_0` Between 1.0573158612197 And 1.68658498678) And (`dist_1` Between 3.6260179152491 And 5.4681062617155)) Then 'z0_2x1_0'
When ((`dist_0` Between 1.0573158612197 And 1.68658498678) And (`dist_1` Between 2.1278369006061 And 3.6260179152491)) Then 'z0_2x1_1'
When ((`dist_0` Between 0 And 1.0573158612197) And (`dist_1` Between 3.6260179152491 And 5.4681062617155)) Then 'z0_3x1_0'
When ((`dist_0` Between 0 And 1.0573158612197) And (`dist_1` Between 2.1278369006061 And 3.6260179152491)) Then 'z0_3x1_1'
When ((`dist_0` Between 2.8723597844095 And 4.3343662110324)) Then 'z0_0'
When ((`dist_0` Between 1.68658498678 And 2.8723597844095)) Then 'z0_1'
When ((`dist_0` Between 1.0573158612197 And 1.68658498678)) Then 'z0_2'
When ((`dist_0` Between 0 And 1.0573158612197)) Then 'z0_3'
When ((`dist_1` Between 3.6260179152491 And 5.4681062617155)) Then 'z1_0'
When ((`dist_1` Between 2.1278369006061 And 3.6260179152491)) Then 'z1_1'
When ((`dist_1` Between 1.3333495959677 And 2.1278369006061)) Then 'z1_2'
When ((`dist_1` Between 0 And 1.3333495959677)) Then 'z1_3'
End As `zone`
From
(Select `lat`, `lng`, `value`,
(acos(0.65292272498833*sin(radians(`lat`)) + 0.75742452772129*cos(radians(`lat`))*cos(radians(`lng`)-(-1.2910922519714))) * 6371) as `dist_0`,
(acos(0.65251345816785*sin(radians(`lat`)) + 0.75777713538338*cos(radians(`lat`))*cos(radians(`lng`)-(-1.2916315412569))) * 6371) as `dist_1`
From `pop`
Where
((`lat` Between 40.714353892125 And 40.810300107875) And (`lng` Between -74.037474145971 And -73.910799854029)) Or
((`lat` Between 40.673205922895 And 40.789544077105) And (`lng` Between -74.081798776797 And -73.928273223203))
)
As FirstCut
)
As Zonecut
这是事情的逻辑:
dist_0
和dist_1
,但可以有任意数量的焦点-我在本例中使用了两个,只是为了说明其工作原理)。这是大圆距离的哈弗公式对此的任何和所有反馈都将不胜感激。MySQL表是海量的(数百万行),并且索引到所有神圣的地狱。运行上面的查询大约需要0.6秒,这还不算太糟糕,但是随着更多的焦点被添加,查询开始需要更长的时间,在这个阶段,我只是在尝试通过SQL逻辑来思考。谢谢。我没有彻底检查过,但这似乎可以缩短那个大的
案例
一些:
CONCAT(
( CASE
WHEN (dist_0 ... ) THEN 'z0_0'
WHEN (dist_0 ... ) THEN 'z0_1'
...
ELSE '' ),
( CASE
WHEN (dist_1 ... ) THEN 'z1_0'
WHEN (dist_1 ... ) THEN 'z1_1'
...
ELSE '' ) ) AS zone
哦,那太聪明了。我会看看是否可以实施;我认为这是可行的。