com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:未知列位于';字段列表';使用标准和映射注释
我有访问结果的标准 第一个Hibernate Dao是com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:未知列位于';字段列表';使用标准和映射注释,mysql,hibernate-mapping,hibernate-criteria,Mysql,Hibernate Mapping,Hibernate Criteria,我有访问结果的标准 第一个Hibernate Dao是 AnswerText answersText = questionManager.getAnswerTextByAnswerIdAndLanguageId(answers.getAnswerId(), 1L); @Override public AnswerText getAnswerTextByAnswerIdAndLanguageId(Number answerId,Number languageId) { C
AnswerText answersText = questionManager.getAnswerTextByAnswerIdAndLanguageId(answers.getAnswerId(), 1L);
@Override
public AnswerText getAnswerTextByAnswerIdAndLanguageId(Number answerId,Number languageId) {
Criteria criteria = sessionFactory.getCurrentSession().createCriteria(AnswerText.class);
criteria.add(Restrictions.eq("answer.answerId", answerId));
criteria.add(Restrictions.eq("languageId", languageId));
List<AnswerText> results = criteria.list();
return (results !=null && !results.isEmpty()? results.get(0): null);
}
Answers.java
@Entity
@Table(name = "ANSWERS")
@Cacheable
@JsonIgnoreProperties(ignoreUnknown = true)
public class Answer {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ANSWER_ID")
private Long answerId;
@Column(name = "QUESTION_ID")
private Long questionId;
@Column(name = "DATE_CREATED")
private Timestamp dateCreated;
@Column(name = "CREATED_BY_ID")
private Long creatorId;
@Column(name = "DATE_MODIFIED")
private Timestamp dateModified;
@Column(name = "MODIFIED_BY_ID")
private Long modifierId;
@OneToMany(fetch = FetchType.EAGER,mappedBy = "answer" )
private Set<AnswerText> answerText = new HashSet<AnswerText>();
//getters and setters
AnswerText.java
@Entity
@Table(name = "ANSWERTEXT")
@Cacheable
@JsonIgnoreProperties(ignoreUnknown = true)
public class AnswerText {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ANSWER_TEXT_ID")
private Long answerTextId;
@ManyToOne
@JoinColumn(name="answerId", insertable=false, updatable=false,
nullable=false)
private Answer answer;
@Column(name = "ANSWER_TEXT")
private String answerText;
@Column(name = "LANGUAGE_ID")
private Long languageId;
//getters and setters
然后我换成了下面的
AnswerText.java
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "ANSWER_ID", nullable = false)
private Answer answer;
Answers.java
@OneToMany(fetch = FetchType.EAGER,mappedBy = "answer" )
@Fetch(FetchMode.JOIN)
private Set<AnswerText> answerText = new HashSet<AnswerText>();
@OneToMany(fetch=FetchType.EAGER,mappedBy=“answer”)
@Fetch(FetchMode.JOIN)
私有集answerText=新HashSet();
这不会产生错误,但会在调用时获取两次结果
第二个HibernateDao调用是
List<Answer> answerList = questionManager.getAnswersByQuestionId(Long.parseLong("2"));
System.out.println("answerList :"+answerList1.size());
@Override
public ArrayList<Answer> getAnswersByQuestionId(Number questionId) {
Criteria criteria = sessionFactory.getCurrentSession().createCriteria(Answer.class);
criteria.add(Restrictions.eq("questionId", questionId));
ArrayList<Answer> answerList = (ArrayList) criteria.list();
return answerList;
}
List-answerList=questionManager.getAnswersByQuestionId(Long.parseLong(“2”);
System.out.println(“answerList:+answerList1.size());
@凌驾
公共阵列列表getAnswersByQuestionId(编号questionId){
Criteria=sessionFactory.getCurrentSession().createCriteria(Answer.class);
标准。添加(限制。情商(“问题ID”,问题ID));
ArrayList answerList=(ArrayList)criteria.list();
返回应答列表;
}
谁能告诉我这里出了什么问题吗。请帮帮我。更改列名做得很好 在我看来,你的多重结果必然会: FetchType.EAGER和 fetchmodejoin如前所述,您将不得不担心重复 结果。另一方面,JOIN创建的查询量最少。 在高延迟环境中,单个连接可能是相当可观的 比多次选择更快。请记住,连接太多数据 可能会给数据库带来压力。 从 使用FetchMode。选择您将得到您想要的结果
List<Answer> answerList = questionManager.getAnswersByQuestionId(Long.parseLong("2"));
System.out.println("answerList :"+answerList1.size());
@Override
public ArrayList<Answer> getAnswersByQuestionId(Number questionId) {
Criteria criteria = sessionFactory.getCurrentSession().createCriteria(Answer.class);
criteria.add(Restrictions.eq("questionId", questionId));
ArrayList<Answer> answerList = (ArrayList) criteria.list();
return answerList;
}