Mysql 如何获得今天的日期-30/-60天？

例如，我希望在60天之前获得今天的确切日期的数据

我尝试了下面的查询，但它选择了60天前到今天的所有记录

(bill_date > DATE_SUB(CURDATE() , INTERVAL 60 DAY)

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我要的是60天前的记录。有人能帮我吗？

根据我对你问题的理解。尝试此查询。请把你的问题弄清楚

SELECT * FROM table
WHERE bill_date BETWEEN DATE_SUB(NOW(), INTERVAL 60 DAY) AND NOW();

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您必须使用

=

而不是

SELECT * FROM table
WHERE bill_date = DATE_SUB(NOW(), INTERVAL 60 DAY);

今天+60天（仅此一天）使用：

SELECT * FROM tableName WHERE bill_date = DATE_ADD(NOW(), INTERVAL 60 DAY);

SELECT * FROM tableName WHERE bill_date = DATE_SUB(NOW(), INTERVAL 60 DAY);

SELECT * FROM tableName 
WHERE bill_date BETWEEN DATE_SUB(NOW(), INTERVAL 60 DAY) AND NOW();

SELECT * FROM tableName 
WHERE bill_date BETWEEN DATE_ADD(NOW(), INTERVAL 60 DAY) AND NOW();

今天-60天（仅此一天）使用：

SELECT * FROM tableName WHERE bill_date = DATE_ADD(NOW(), INTERVAL 60 DAY);

SELECT * FROM tableName WHERE bill_date = DATE_SUB(NOW(), INTERVAL 60 DAY);

SELECT * FROM tableName 
WHERE bill_date BETWEEN DATE_SUB(NOW(), INTERVAL 60 DAY) AND NOW();

SELECT * FROM tableName 
WHERE bill_date BETWEEN DATE_ADD(NOW(), INTERVAL 60 DAY) AND NOW();

从现在到-/+60天之间的所有记录：

SELECT * FROM tableName WHERE bill_date = DATE_ADD(NOW(), INTERVAL 60 DAY);

SELECT * FROM tableName WHERE bill_date = DATE_SUB(NOW(), INTERVAL 60 DAY);

SELECT * FROM tableName 
WHERE bill_date BETWEEN DATE_SUB(NOW(), INTERVAL 60 DAY) AND NOW();

SELECT * FROM tableName 
WHERE bill_date BETWEEN DATE_ADD(NOW(), INTERVAL 60 DAY) AND NOW();

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我很困惑。你是说60天前还是之前的记录？据我所知，在这个答案中首先给出的查询将起到作用，并根据需要获取当天的数据