Mysql 编写一个查询,显示累计罚款超过1000辆的所有汽车的累计罚款总额
我不知道如何用SQL编写查询 这是我的桌子Mysql 编写一个查询,显示累计罚款超过1000辆的所有汽车的累计罚款总额,mysql,Mysql,我不知道如何用SQL编写查询 这是我的桌子 CREATE TABLE offences ( oOffenceID VARCHAR (30), oDescription VARCHAR (200), oMaximumFine INT (10), CONSTRAINT o_pk PRIMARY KEY (oOffenceID) ); CREATE TABLE drivers ( dPersonID VARCHAR (30), dLicenseNumber INT (20), dLicenseRem
CREATE TABLE offences (
oOffenceID VARCHAR (30),
oDescription VARCHAR (200),
oMaximumFine INT (10),
CONSTRAINT o_pk
PRIMARY KEY (oOffenceID)
);
CREATE TABLE drivers (
dPersonID VARCHAR (30),
dLicenseNumber INT (20),
dLicenseRemoved ENUM('yes','no'),
dExpiryDate DATE,
CONSTRAINT d_pk
PRIMARY KEY (dLicenseNumber),
CONSTRAINT d_fk
FOREIGN KEY (dPersonId)
REFERENCES People (pPersonID)
);
CREATE TABLE people (
pPersonID VARCHAR (30),
pName VARCHAR (30),
pAddress VARCHAR (50),
pNIN VARCHAR (30),
CONSTRAINT p_pk
PRIMARY KEY (pPersonID)
);
CREATE TABLE vehicle (
vOwnerID VARCHAR (30),
vColour VARCHAR (30),
vModel VARCHAR (30),
vMake VARCHAR (30),
vVehicleID VARCHAR (30),
CONSTRAINT v_pk
PRIMARY KEY (vVehicleID),
CONSTRAINT v_fk
FOREIGN KEY (vOwnerID)
REFERENCES People (pPersonID)
);
CREATE TABLE fines (
fFineID INT (30) AUTO_INCREMENT,
fVehicleID VARCHAR (30),
fPersonID VARCHAR (30),
fTime DATE,
fAmount INT (10),
fOfficerStatement VARCHAR (500),
fOffenceID VARCHAR (30),
CONSTRAINT f_pk
PRIMARY KEY (fFineID),
CONSTRAINT f_fk
FOREIGN KEY (fVehicleID)
REFERENCES vehicle (vVehicleID),
CONSTRAINT f_fk1
FOREIGN KEY (fPersonID)
REFERENCES people (pPersonID),
CONSTRAINT f_fk2
FOREIGN KEY (fOffenceID)
REFERENCES offences (oOffenceID)
);
我需要一个查询,显示汽车ID、车主姓名以及累计罚款超过1000辆的所有汽车的累计罚款总额。有人知道怎么做吗?希望这能让你朝着正确的方向前进:
select fVehicleId,p.pName,sum(fi.totalFines) as totalFinesOver1000ForPerson
from
(select fVehicleId,sum(fAmount) as totalFines
from fines f
group by fVehicleId
having sum(fAmount) > 1000) fi
inner join vehicle v on v.vVehicleID = fi.fVehicleId
inner join people p on v.vOwnerId = p.pPersonId
group by fVehicleId,p.pName;
这应该行得通我能问一下p.pName是什么意思吗。在pName之前是什么意思?你是对的-这在SQL中称为“别名”。您可以在这里了解更多信息:经过仔细分析,此解决方案不起作用,但它确实将我介绍给了小组,让我找到了此解决方案……
从车辆、人员、罚款中选择vVehicleID、pName、SUM(fAmount),其中fAmount>1000,pPersonID=fPersonID,vVehicleID=fVehicleID按fVehicleID分组
Select a.vVehicleID,
b.pName,
sum(d.fAmount) fine
from vehicle a,people b,fines d,drivers e
where a.vVehicleID=d.vVehicleID and d.fPersonID=e.dPersonID and d.fPersonID=a.vOwnerID and
b.pPersonID = e.dPersonID
group by a.vVehicleID,b.pNamem
having fine > 1000;