从每个月开始重新排列MySQL表

这是我的目标表

retail_id month tgt_volume product_type 1 2013-11-01 2 Bar 2 2013-10-01 1 Touch 3 2013-09-01 1 Bar 4 2013-10-01 5 Smart 5 2013-10-01 8 Bar 3 2013-08-01 2 Smart 2 2013-08-01 5 Bar 3 2013-07-01 7 Bar 3 2013-07-01 2 Smart

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您可以在聚合函数中使用

CASE

语句来实现这一点：

SELECT  Retail_ID,
        SUM(CASE WHEN product_Type = 'Bar' THEN tgt_Volume ELSE 0 END) AS Bar,
        SUM(CASE WHEN product_Type = 'smart' THEN tgt_Volume ELSE 0 END) AS Smart,
        SUM(CASE WHEN product_Type = 'Touch' THEN tgt_Volume ELSE 0 END) AS Touch,
        SUM(tgt_Volume) AS Total,
        Month
FROM    targets 
GROUP BY RetailId, Month;

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谢谢。但如果我在一个普通月份插入其他零售id。它没有显示正确的数据。例如，如果我插入（2，'2013-07-01'，7，'Bar'），则2013-07-01月应为2和3零售id插入2行。请查看您的again@GarethD . . . 我将您的查询更改为“按

零售Id

和

月进行分组”，因为我认为这就是OP所寻找的。
SELECT   DISTINCT t.retail_id,bar_vol.bar,smart_vol.smart,touch_vol.touch,total.total,t.month FROM targets t
LEFT JOIN
(SELECT SUM(tgt_volume) AS bar,retail_id FROM targets t1 WHERE t1.product_type='Bar' GROUP BY retail_id) AS bar_vol  
ON  t.retail_id=bar_vol.retail_id
LEFT JOIN
(SELECT SUM(tgt_volume) AS smart,retail_id FROM targets t2 WHERE t2.product_type='Smart' GROUP BY retail_id) AS smart_vol  
ON  t.retail_id=smart_vol.retail_id
LEFT JOIN
(SELECT SUM(tgt_volume) AS touch,retail_id FROM targets t3 WHERE t3.product_type='Touch' GROUP BY retail_id) AS touch_vol  
ON  t.retail_id=touch_vol.retail_id
LEFT JOIN
(SELECT SUM(tgt_volume) AS total,retail_id FROM targets t4  GROUP BY retail_id) AS total  
ON  t.retail_id=total.retail_id

SELECT  Retail_ID,
        SUM(CASE WHEN product_Type = 'Bar' THEN tgt_Volume ELSE 0 END) AS Bar,
        SUM(CASE WHEN product_Type = 'smart' THEN tgt_Volume ELSE 0 END) AS Smart,
        SUM(CASE WHEN product_Type = 'Touch' THEN tgt_Volume ELSE 0 END) AS Touch,
        SUM(tgt_Volume) AS Total,
        Month
FROM    targets 
GROUP BY RetailId, Month;