Mysql 使用GROUP BY从表中选择MAX（）

我有一些桌子：

name    dep_id  salary
Vasia   5       1000
Oleg    5       1300
Vitia   4       1000
Sacha   3       1100
Kolia   5       1600
Lesha   2       1400
Sergey  4       1200
Marina  5       1300
Olga    5       1500
Igor    4       1400
Valia   3       1500
Erema   4       1500

我需要得到他所在部门中工资最高的员工的姓名

i、 我需要

 Lesha   1400
 Valia   1500
 Erema   1500
 Kolia   1600

我试过：

SELECT name, max(salary) FROM employees GROUP BY dep_id

但这会显示不正确的值

我该怎么做

select e1.*
from employees e1
join
(
  SELECT dep_id, max(salary) as msal
  FROM employees
  GROUP BY dep_id
) e2 on e1.dep_id = e2.dep_id
    and e1.salary = e2.msal

结果:

name    Sallary
---------------
Lesha   1400
Valia   1500
Erema   1500
Kolia   1600

演示

结果:

name    Sallary
---------------
Lesha   1400
Valia   1500
Erema   1500
Kolia   1600

---

在

中进行演示，尝试以下查询以获得所需的输出：

    select name,sallary from employees t1 where (dep_id,sallary) in
    (select dep_id,max(sallary) from employees group by dep_id);

---

请尝试以下查询以获得所需的输出：

    select name,sallary from employees t1 where (dep_id,sallary) in
    (select dep_id,max(sallary) from employees group by dep_id);