Mysql 选择除最高记录外的所有记录

我有三张桌子

 Page                           Revision                                   Text                       
 +-----------+-------------+    +-----------+-------------+----------+     +-------------+---------+
 | page_id   | rev_id      |    | rev _id   | rev_text_id | page_id  |     | rev_text_id | text    |
 +-----------+-------------+    +-----------+-------------+----------+     +-------------+---------+
 |      1    |     2       |    |      1    |     1       |    1     |     |      1      |     A   |
 +--------------------------    +------------------------------------+     +-----------------------+
 |      2    |     5       |    |      2    |     2       |    1     |     |      2      |     B   |
 +-------------------------+    +------------------------------------+     +-----------------------+
                                |      3    |     3       |    2     |     |      3      |     C   |
                                +------------------------------------+     +-----------------------+
                                |      4    |     4       |    2     |     |      4      |     D   |
                                +------------------------------------+     +-----------------------+
                                |      5    |     4       |    2     |               
                                +------------------------------------+               

我期望的输出是：

 +--------+-------------+
 | rev_id | rev_text_id |
 +--------+-------------+
 |   1    |      1      |
 +----------------------+
 |   3    |      3      |
 +----------------------+
 |   4    |             |
 +----------------------+

我的目标是找到可以在单个查询中从每个表中删除的rev_id和rev_text_id。由于修订表可以为多个修订保留相等的rev_text_id，因此我需要排除第2页示例4中每个页面最高的rev_text_id

我开始涉足以下领域：

 SELECT
 r.rev_id,r.rev_text_id
 FROM revision r, page p, text t
 WHERE p.page_id = r.page_id
 AND t.rev_text_id = r.rev_text_id 
 AND p.rev_id != r.rev_id
 AND r.rev_text_id not in (
      SELECT max(r.rev_text_id)
      FROM revision AS r, page AS p
      WHERE r.rev_id = p.rev_id
 );

但这会跳过我所需输出中rev_id 4的记录，并且不包括空情况。

尝试以下操作：

SELECT r.`rev_id`, r.`rev_text_id`
FROM `Revision` AS r
WHERE r.`rev_text_id` NOT IN (SELECT r.`rev_text_id`
                              FROM `Revision` AS r, `Page` AS p
                              WHERE r.`rev_id` = p.`page_latest`;)
ORDER BY r.`rev_id`;

---

这基本上捕获了与PergEx最新相同的RevIdID，查找与RevIdID相关联的RevEthTythID ID，并使用那些RevTrimeStID ID作为筛选器。

请显示当前SQL Quer思，提供一个SQLFIDLE，并且，为了大家的理智，考虑将列重命名为RevIdID，PaGyId，和rev_text_id。该查询不会正确返回rev_id 4，因为您会过滤掉那些与page_latest具有相同rev_id的修订。我想要的输出包括rev_id 4，输出中没有附加rev_text_id。我猜这必须通过连接来实现？我不知道在纯SQL中是否有实现这一点的方法。我不知道有什么办法能把细胞分成那样的一行。在查询之后，您可能必须在PHP中处理该问题。