Mysql 查找每个站点至少访问过两个不同国家/地区的唯一用户数

查找每个站点至少访问过两个不同国家/地区的唯一用户数。 给定时间戳、用户、国家/地区、站点

我认为这个查询应该是这样的，但它似乎不对，因为它对每个站点的唯一用户数给出了非常相似的答案

SELECT site_id, COUNT (DISTINCT user_id) 
FROM SWE 
GROUP BY site_id
HAVING COUNT(country_id) >=2
ORDER BY site_id ASC;

试试这个-

SELECT A.user_id,B.site_id,COUNT(DISTINCT B.country_id) [Country Visited]
FROM
(
    SELECT user_id 
    FROM SWE
    GROUP BY user_id
    HAVING COUNT(site_id) = COUNT(DISTINCT site_id)
)A
INNER JOIN SWE B ON A.user_id = B.user_id
GROUP BY A.user_id,B.site_id
HAVING COUNT(DISTINCT B.country_id) >= 2

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两级聚合是编写查询的最自然的方式：

select site_id, count(*)
from (select user_id, site_id, count(*)
      from swe
      group by user_id, site_id
      having min(country) <> max(country)  -- or count(distinct country) >= 2
     ) us
group by site_id;