Node.js 云函数查询冲突
我正在编写一个谷歌云函数来创建聊天室,用户从移动应用程序向firestore发送一个请求,请求中包含他的兴趣,然后触发函数读取firestore中所有未决的请求,直到找到与用户匹配的人。当这种情况发生时,云函数将删除这两个请求并创建聊天室,但我的问题是,如果多个用户同时发送请求,云函数将读取理论上应该已经删除的请求。这是我的代码:Node.js 云函数查询冲突,node.js,firebase,google-cloud-firestore,google-cloud-functions,Node.js,Firebase,Google Cloud Firestore,Google Cloud Functions,我正在编写一个谷歌云函数来创建聊天室,用户从移动应用程序向firestore发送一个请求,请求中包含他的兴趣,然后触发函数读取firestore中所有未决的请求,直到找到与用户匹配的人。当这种情况发生时,云函数将删除这两个请求并创建聊天室,但我的问题是,如果多个用户同时发送请求,云函数将读取理论上应该已经删除的请求。这是我的代码: const functions = require('firebase-functions'); const admin = require('firebase-ad
const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp();
const db = admin.firestore();
exports.cargarPeticion = functions.firestore.document('/Requests/{id}').onCreate((snap, context) => {
const newValue = snap.data();
const uid = newValue.uid;
const age = newValue.age;
const sex = newValue.sex;
const manInterest = newValue.Hombres;
const womenInterest = newValue.Mujeres;
const loveInterest = newValue.Love;
const friendInterest = newValue.Friendship;
const timestamp = newValue.Timestamp;
const minAgeInterest = newValue.ageMin;
const maxAgeInterest = newValue.ageMax;
var ciclo = true;
db.collection('Requests').orderBy('Timestamp').get()
.then((snapshot) => {
try{
snapshot.forEach((doc) => {
var data = doc.data();
if(data.uid !== uid){
console.log("NUEVO");
console.log(doc.id, '=>', data.uid);
if(loveInterest === data.Love || friendInterest === data.Friendship){
if(data.age >= minAgeInterest &&
data.age <= maxAgeInterest &&
((sex === "H" && data.Hombres === "true") || (sex === "M" && data.Mujeres === "true"))){
if(age >= data.ageMin &&
age <= data.ageMax &&
((manInterest === "true" && data.sex === "H") || (womenInterest === "true" && data.sex === "M"))){
var arrayUsers = [uid, data.uid];
console.log("ID SALA");
console.log(uid.substring(0, 8) + data.uid.substring(0, 7) + doc.id.substring(0, 7));
db.collection('chatRoom').doc(uid.substring(0, 8) + data.uid.substring(0, 7) + doc.id.substring(0, 7)).set({
arrayUsers: arrayUsers,
uid1: uid,
uid2: data.uid,
chatRoomId : uid.substring(0, 8) + data.uid.substring(0, 7) + doc.id.substring(0, 7),
ultimoMensaje: '',
ultimoEscritorUid : '',
ultimoMensajeTiempo : 0
});
db.collection('Requests').doc(doc.id).delete();
db.collection('Requests').doc(snap.id).delete();
throw exception
}
}
}
}
});
}catch(exception){
console.log(exception);
}
return null;
})
.catch((err) => {
console.log('Error getting documents', err);
});
})
const functions=require('firebase-functions');
const admin=require('firebase-admin');
admin.initializeApp();
const db=admin.firestore();
exports.cargarPeticion=functions.firestore.document('/Requests/{id}').onCreate((快照,上下文)=>{
const newValue=snap.data();
const uid=newValue.uid;
const age=newValue.age;
const sex=newValue.sex;
const manInterest=newValue.Hombres;
const womenInterest=newValue.Mujeres;
const loveInterest=newValue.Love;
const friendInterest=newValue.友谊;
const timestamp=newValue.timestamp;
const minAgeInterest=newValue.ageMin;
const maxAgeInterest=newValue.ageMax;
var ciclo=真;
db.collection('Requests').orderBy('Timestamp').get()
。然后((快照)=>{
试一试{
snapshot.forEach((doc)=>{
var data=doc.data();
如果(data.uid!==uid){
控制台日志(“新”);
console.log(doc.id'=>',data.uid);
如果(loveInterest==data.Love | | friendInterest==data.friendy){
如果(data.age>=minAgeInterest&&
data.age=data.ageMin&&
年龄{
console.log('获取文档时出错',err);
});
})
为防止并发数据库更新创建不一致的数据集,您需要执行更新。使用事务时,允许第一个实例修改数据,并自动重试对相同数据的任何冲突更新,直到没有冲突为止