Node.js Mongoose将附加集合连接到两个聚合集合

Node.js Mongoose将附加集合连接到两个聚合集合,node.js,mongodb,mongoose,Node.js,Mongodb,Mongoose,这是我需要在我的个人项目中实现的新要求。我使用聚合成功加入了两个集合。现在,我需要加入一个新集合。请参阅下面的代码: 学生模型: { fullname: { type: String, required: true }, email: { type: String, required: true }, } 考试模式: { test: { type: String, required: false }, top10: [ type: { studentId:

这是我需要在我的个人项目中实现的新要求。我使用聚合成功加入了两个集合。现在,我需要加入一个新集合。请参阅下面的代码:

学生模型:

{
  fullname: { type: String, required: true },
  email: { type: String, required: true },
}
考试模式:

{
  test: { type: String, required: false },
  top10: [
    type: {
      studentId: { type: String, required: true },
      score: { type: Number, required: false },
    }
  ]
}
聚合集合:

db.exams.aggregate([
{ $unwind: "$top10" },
{
$lookup: {
  from: "students",
  localField: "top10.studentId",
  foreignField: "_id",
  as: "students"
}
},
{ $addFields: { students: { $arrayElemAt: ["$students", 0] } } },
{
$group: {
  _id: "$_id",
  test: { $first: "$test" },
  students: {
    $push: {
      studentId: "$top10.studentId",
      score: "$top10.score",
      fullname: "$students.fullname"
    }
  }
}
}
])
现在,第三个集合称为教师

教师模式:

{
  fullName: { type: String, required: false },
  studentId: { type: String, required: false }
}
预期产出应为:

{
 "test": "Sample Test #1",
 "students": [
        {
            "studentId": "5f22ef443f17d8235332bbbe",
            "fullname": "John Smith",
            "score": 11,
            "teacher": "Dr. Hofstadter"
            
        },
        {
            "studentId": "5f281ad0838c6885856b6c01",
            "fullname": "Erlanie Jones",
            "score": 9,
            "teacher": "Mr. Roberts"
        },
        {
            "studentId": "5f64add93dc79c0d534a51d0",
            "fullname": "Krishna Kumar",
            "score": 5,
            "teacher": "Ms. Jamestown"
        }
    ]
}

感谢您的帮助。谢谢!

您可以在$group管道之前再添加这两个管道

  • $lookup
    与教师加入集合
  • $addFields
    获取转换数组到对象
  • $group
    在学生数组中添加教师姓名

谢谢你的帮助!我从你那里学到了一些东西。另一个问题。如果学生没有老师,我们该如何处理?我想为此显示空字符串。我已使用$ifNull运算符进行了更新,因为如果不是fount,它将返回null。谢谢@turivishal.Btw,是否可以在对象而不是数组中显示结果集?添加两个在$unwind students和$replaceWith students末尾的新管道您需要在查询后执行此操作,以便从零位置访问对象。例如
let response=wait aggregate();console.log(response[0])
  {
    $lookup: {
      from: "teacher",
      localField: "top10.studentId",
      foreignField: "studentId",
      as: "students.teacher"
    }
  },
  {
    $addFields: {
      "students.teacher": { $arrayElemAt: ["$students.teacher", 0] }
    }
  },
  {
    $group: {
      _id: "$_id",
      test: { $first: "$test" },
      students: {
        $push: {
          studentId: "$top10.studentId",
          score: "$top10.score",
          fullname: "$students.fullname",
          teacher: { $ifNull: ["$students.teacher.fullname", ""] }
        }
      }
    }
  }