Node.js npm postbuild脚本在重命名文件时出错

我已经为npm postbuild制作了一个节点脚本，在react应用程序中生成构建后，该脚本执行简单的任务来重命名构建文件夹中的文件

这是文件

postbuild.js

let fs = require("fs");
let path = require("path");

const oldJSPath = path.join(__dirname, "build", "static", "js", "*.js");
const newJSPath = path.join(__dirname, "build", "static", "js", "bundle.js");

const oldCSSPath = path.join(__dirname, "build", "static", "css", "*.css");
const newCSSPath = path.join(__dirname, "build", "static", "css", "bundle.css");

fs.renameSync(oldJSPath, newJSPath);
fs.renameSync(oldCSSPath, newCSSPath);

现在的问题是，我不断得到错误：

enoint:没有这样的文件或目录，请重命名C:\Users\HDL\Documents\demo redux app\build\static\js\*.js'->“C:\Users\HDL\Documents\demo redux app\build\static\js\bundle.js”

let fs = require("fs");
let path = require("path");

const oldJSPath = path.join(__dirname, "build", "static", "js", "*.js");
const newJSPath = path.join(__dirname, "build", "static", "js", "bundle.js");

const oldCSSPath = path.join(__dirname, "build", "static", "css", "*.css");
const newCSSPath = path.join(__dirname, "build", "static", "css", "bundle.css");

fs.renameSync(oldJSPath, newJSPath);
fs.renameSync(oldCSSPath, newCSSPath);

即使构建目录中确实存在文件和目录

build

dir的结构：

-build
  -static
    -css
      *.css
    -js
      *.js

    -media
      *.png, jpg etc

不知道这是否必要，但这里是

package.json

：

{
  "name": "demo-redux-app",
  "version": "0.1.0",
  "private": true,
  "dependencies": {
    "react": "^16.4.1",
    "react-dom": "^16.4.1",
    "react-redux": "^5.0.7",
    "react-scripts": "1.1.4",
    "redux": "^4.0.0",
    "redux-promise-middleware": "^5.1.1",
    "redux-thunk": "^2.3.0"
  },
  "scripts": {
    "start": "react-scripts start",
    "build": "react-scripts build",
    "postbuild": "node postbuild.js",
    "test": "react-scripts test --env=jsdom",
    "eject": "react-scripts eject"
  }
}

---

Node.js

fs

不支持通配符

如果目的是匹配

*.js

中的第一个文件，并将其重命名为

bundle.js

，则可以使用globs：

const globby = require('globby');

const newJSPath = path.join(__dirname, "build", "static", "js", "bundle.js");
const oldJSWildcardPath = path.join(__dirname, "build", "static", "js", "*.js");
const [oldJSPath] = globby.sync(oldJSWildcardPath);
if (oldJSPath) {
  fs.renameSync(oldJSPath, newJSPath);
}
...

或使用regexp：

const newJSPath = path.join(__dirname, "build", "static", "js", "bundle.js");
const oldJSDirPath = path.join(__dirname, "build", "static", "js");
const [oldJSPath] = fs.readdirSync(oldJSDirPath).filter(filename => /.js$/.test(filename));
if (oldJSPath) {
  fs.renameSync(oldJSPath, newJSPath);
}
...

---

fs不支持通配符。newJSPath应该做什么？您正在尝试将多个文件重命名为单个build\static\js\bundle.js文件，是吗？well build只在js目录中生成一个以名称

main*.js

开头的js文件，它位于

static

dir中，所以我尝试将单个文件重命名为

bundle.js

，是的，我刚刚知道fs不支持通配符除了安装之外还有更好的解决方案吗

glob fs

除非您想用regexp解析文件列表，否则您无论如何都需要glob。glob fs不够好，我建议globby。