Node.js 更快的媒体流图像捕获（在nodejs中将媒体流读取为缓冲区）

编辑：我需要在现场执行此操作。我迫不及待地想等溪流结束

我从electron的

desktopCapturer

获取

MediaStream

对象：

navigator.mediaDevices.getUserMedia({
  audio: false,
  video: {
    mandatory: {
      chromeMediaSource: 'desktop',
      chromeMediaSourceId: source.id,
      minWidth: 800,
      maxWidth: 800,
      minHeight: 800,
      maxHeight: 800,
    },
  },
})
.then((stream) => {

我正在尝试使用

ImageCapture

获取静止帧的节点

缓冲区

：

  const track = stream.getVideoTracks()[0];
  const capturedImage = new ImageCapture(track);

  capturedImage // This takes 200ms for 1000x1000
    .takePhoto()
    .then(blob => {
      toBuffer(blob, function (err, buffer) { // 1.5 ms
        if (err) throw err;
          // TODO: Do some opencv magic with node buffer
      });
    })
    .catch(error => console.error('takePhoto() error:', error));

---

但是拍摄照片要花很长时间。有没有可能使过程更快？我是否可以直接在

nodejs

中访问

MediaStream

。事实上，它真的很有表现力

}).then((stream) => {
  const video = document.createElement('video');
  video.srcObject = stream;
  video.onloadedmetadata = () => {
  video.play();
  setInterval(() => {
    const canvas = document.createElement('canvas');
    canvas.getContext('2d').drawImage(video, 0, 0, 800, 800);
    canvas.toBlob(blob => {
      toBuffer(blob, function (err, buffer) {
        if (err) throw err;
        // do some magic with buffer
      });
    });
  }, 40);
};