Objective c 使用RestKit 0.20的谷歌地理编码API

Objective c 使用RestKit 0.20的谷歌地理编码API,objective-c,json,google-maps,ios6,restkit,Objective C,Json,Google Maps,Ios6,Restkit,我不知道如何优雅地解析这个响应。我试图将不同的字段类型与包含以下属性的对象相匹配 @property (nonatomic) NSString *name; @property (nonatomic) NSString *address; @property (nonatomic) NSString *city; @property (nonatomic) NSString *postalcode; @property (nonatomic) NSString *district; @prope

我不知道如何优雅地解析这个响应。我试图将不同的字段类型与包含以下属性的对象相匹配

@property (nonatomic) NSString *name;
@property (nonatomic) NSString *address;
@property (nonatomic) NSString *city;
@property (nonatomic) NSString *postalcode;
@property (nonatomic) NSString *district;
@property (nonatomic) NSString *country;
过去我查字典时,子字段与我搜索的字段匹配

 {
   "results" : [
      {
         "address_components" : [
            {
               "long_name" : "10",
               "short_name" : "10",
               "types" : [ "street_number" ]
            },
            {
               "long_name" : "Warschauer Straße",
               "short_name" : "Warschauer Straße",
               "types" : [ "route" ]
            },
            {
               "long_name" : "Friedrichshain",
               "short_name" : "Friedrichshain",
               "types" : [ "sublocality", "political" ]
            },
            {
               "long_name" : "Friedrichshain-Kreuzberg",
               "short_name" : "Friedrichshain-Kreuzberg",
               "types" : [ "sublocality", "political" ]
            },
            {
               "long_name" : "Berlin",
               "short_name" : "Berlin",
               "types" : [ "locality", "political" ]
            },
            {
               "long_name" : "Berlin",
               "short_name" : "Berlin",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "Germany",
               "short_name" : "DE",
               "types" : [ "country", "political" ]
            },
            {
               "long_name" : "10243",
               "short_name" : "10243",
               "types" : [ "postal_code" ]
            }
         ],
         "formatted_address" : "Warschauer Straße 10, 10243 Berlin, Germany",
         "geometry" : {
            "location" : {
               "lat" : 52.51329350,
               "lng" : 13.45246930
            },
            "location_type" : "ROOFTOP",
            "viewport" : {
               "northeast" : {
                  "lat" : 52.51464248029150,
                  "lng" : 13.45381828029150
               },
               "southwest" : {
                  "lat" : 52.51194451970850,
                  "lng" : 13.45112031970850
               }
            }
         },
         "types" : [ "street_address" ]
      }
   ],
   "status" : "OK"
}
如前所述,使用Restkit映射此对象没有优雅的方法,相反,您可以将此格式直接映射到一个“丑陋的对象”,并使用另一个具有所需接口的对象包装该对象

比如:

@interface MYMappedAddress : NSObject

@property (nonatomic) NSArray *addressComponents;
@property (nonatomic) NSArray *types;
@property (nonatomic) MYGeometry *geometry;
@property (nonatomic) NSString * formattedAddress;

@end

@interface MYAddress : MYMappedAddress

@property (nonatomic) NSString *name;
@property (nonatomic) NSString *address;
@property (nonatomic) NSString *city;
@property (nonatomic) NSString *postalcode;
@property (nonatomic) NSString *district;
@property (nonatomic) NSString *country;

@end

嗯。我想出了以下解决办法。我已经定义了一个字典并重写了Setter,以便将传入的字典解析到我自己的解析器中:

-(void)addressByGoogle: (NSDictionary*)newAddressComponents{

    for (NSArray *googleResult in newAddressComponents) {

        for (NSArray *fields in googleResult) {

            if ([[fields valueForKey:@"types"] count] >= 1) {

                NSString *googleType = [[fields valueForKey:@"types"] objectAtIndex:0];

                if ( [googleType isEqualToString:@"sublocality"]) {
                    self.district = [fields valueForKey:@"long_name"];
                }

                if ( [googleType isEqualToString:@"country"]) {
                    self.country = [fields valueForKey:@"long_name"];
                }

                if ( [googleType isEqualToString:@"locality"]) {
                    self.city = [fields valueForKey:@"long_name"];
                }

                if ( [googleType isEqualToString:@"street_number"]) {
                    self.streetnumber = [fields valueForKey:@"long_name"];
                }

                if ( [googleType isEqualToString:@"route"]) {
                    self.address = [fields valueForKey:@"long_name"];
                }

                if ( [googleType isEqualToString:@"postal_code"]) {
                    self.postalcode = [fields valueForKey:@"long_name"];
                }
                if ( [googleType isEqualToString:@"administrative_area_level_1"]) {
                    self.adminAreaLevel1 = [fields valueForKey:@"long_name"];
                }
                if ( [googleType isEqualToString:@"administrative_area_level_2"]) {
                    self.adminAreaLevel2 = [fields valueForKey:@"long_name"];
                }
            }

        }
    }

}

- (void) setAddressComponents:(NSDictionary *)newAddressComponents{
    [self addressByGoogle: newAddressComponents];
}
没有“优雅”的方式。只需硬编码完整的getter,将它们映射到JSON,正如您在这里看到的那样。