Objective c 如何在objective c中生成字母数字的正则表达式

如何生成一个包含char和number的正则表达式。如果只是字母或数字，它应该返回false

例如：

我的正则表达式：

[a-z]|[0-9]

使用

或者，一个可能更高效的版本：

^(?=[^A-Za-z]*[A-Za-z])(?=[^0-9]*[0-9])[0-9A-Za-z]+$

看

消除：

NODE                     EXPLANATION
--------------------------------------------------------------------------------
  ^                        the beginning of the string
--------------------------------------------------------------------------------
  (?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
--------------------------------------------------------------------------------
    [A-Za-z]                 any character of: 'A' to 'Z', 'a' to 'z'
--------------------------------------------------------------------------------
  )                        end of look-ahead
--------------------------------------------------------------------------------
  (?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
--------------------------------------------------------------------------------
    [0-9]                    any character of: '0' to '9'
--------------------------------------------------------------------------------
  )                        end of look-ahead
--------------------------------------------------------------------------------
  [0-9A-Za-z]+             any character of: '0' to '9', 'A' to 'Z',
                           'a' to 'z' (1 or more times (matching the
                           most amount possible))
--------------------------------------------------------------------------------
  $                        before an optional \n, and the end of the
                           string

---

感谢您将问题更新为更具体的内容。您可以使用

^（？[a-z]+\d+\d+[a-z]+）$

（如果还需要大写变体，请将

[a-z]

更改为

[a-zA-z]

）。或者，如果只需要确保每个字符集都存在（但允许正则表达式匹配任何字符，如

），则可以使用

^（？=[^a-z]*[a-z]）（？=\D*\D）

*？

无效。相反，使用

[^a-zA-Z]*

和

\D*

（并考虑

\n

，使用以下内容）<代码>^（？=[^a-zA-Z\n]*[a-zA-Z]）（？：[^\d\n]*[0-9]）[0-9A-zA-Z]+$比您当前的模式更有效。

^(?=[^A-Za-z]*[A-Za-z])(?=[^0-9]*[0-9])[0-9A-Za-z]+$

NODE                     EXPLANATION
--------------------------------------------------------------------------------
  ^                        the beginning of the string
--------------------------------------------------------------------------------
  (?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
--------------------------------------------------------------------------------
    [A-Za-z]                 any character of: 'A' to 'Z', 'a' to 'z'
--------------------------------------------------------------------------------
  )                        end of look-ahead
--------------------------------------------------------------------------------
  (?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
--------------------------------------------------------------------------------
    [0-9]                    any character of: '0' to '9'
--------------------------------------------------------------------------------
  )                        end of look-ahead
--------------------------------------------------------------------------------
  [0-9A-Za-z]+             any character of: '0' to '9', 'A' to 'Z',
                           'a' to 'z' (1 or more times (matching the
                           most amount possible))
--------------------------------------------------------------------------------
  $                        before an optional \n, and the end of the
                           string