Oop Lua复数类算法

我有一些用标准二进制运算符==，>，实现的lua代码，您可以在这里阅读理论：
是复数实现的一个例子。 我可以粘贴该示例中的一些代码

-- complex.add( cx1, cx2 )
-- add two numbers; cx1 + cx2
function complex.add( cx1,cx2 )
   return setmetatable( { cx1[1]+cx2[1], cx1[2]+cx2[2] }, complex_meta )
end

-- complex.sub( cx1, cx2 )
-- subtract two numbers; cx1 - cx2
function complex.sub( cx1,cx2 )
   return setmetatable( { cx1[1]-cx2[1], cx1[2]-cx2[2] }, complex_meta )
end

--// metatable functions
complex_meta.__add = function( cx1,cx2 )
   local cx1,cx2 = complex.to( cx1 ),complex.to( cx2 )
   return complex.add( cx1,cx2 )
end
complex_meta.__sub = function( cx1,cx2 )
   local cx1,cx2 = complex.to( cx1 ),complex.to( cx2 )
   return complex.sub( cx1,cx2 )
end

-- complex.add( cx1, cx2 )
-- add two numbers; cx1 + cx2
function complex.add( cx1,cx2 )
   return setmetatable( { cx1[1]+cx2[1], cx1[2]+cx2[2] }, complex_meta )
end

-- complex.sub( cx1, cx2 )
-- subtract two numbers; cx1 - cx2
function complex.sub( cx1,cx2 )
   return setmetatable( { cx1[1]-cx2[1], cx1[2]-cx2[2] }, complex_meta )
end

--// metatable functions
complex_meta.__add = function( cx1,cx2 )
   local cx1,cx2 = complex.to( cx1 ),complex.to( cx2 )
   return complex.add( cx1,cx2 )
end
complex_meta.__sub = function( cx1,cx2 )
   local cx1,cx2 = complex.to( cx1 ),complex.to( cx2 )
   return complex.sub( cx1,cx2 )
end