我可以在oracle pl/sql developer中使用此代码吗

我正在PL/SQLDeveloper中尝试这段代码，但它没有执行任何操作。如何使用此代码查找列值包含特定值的所有表

declare
    num_rows number;
    sql_text varchar2(250);
    sql_info varchar2(100);
begin
    dbms_output.enable(1000000);
    for x in (select table_name, column_name from all_tab_columns
               where data_type in ('VARCHAR','VARCHAR2','CHAR')
                 and owner='SYSTEM')
    loop
         sql_text:='select count(*) into :num_rows from SYSTEM.'||x.table_name||' where '||x.column_name||' like ''%10305698%''';
         -- dbms_output.put_line (sql_text);
         execute immediate sql_text into num_rows;
         if num_rows>0 
         then 
              sql_info:='Table: '||x.table_name||' contains the string';
              dbms_output.put_line (sql_info);
         end if;
    end loop;
end;
/

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下面的演示是为了：

搜索字符类型 让我们在SCOTT模式中寻找价值之王

搜索数字类型 让我们在SCOTT模式中查找值20

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您的编译器是什么？我在SQL*Plus上显示的演示也将在SQL Developer和PL/SQL Developer上运行。@如果PL/SQL编译器在数据库中，您的代码将在PL/SQL Developer上运行，但结果不显示可能cols view不会为您返回任何结果。您是否打开了SERVEROUTPUT？您的代码对我来说很好。您的用户是否具有查看系统表的权限？可能ALL_TAB_COLUMNS查询没有为您返回任何内容。顺便说一句，“VARCHAR”、“VARCHAR2”、“CHAR”中的数据类型可以简化为数据类型，如“%CHAR%”。此外，PL/SQL Developer不是Oracle产品。

SQL> variable val varchar2(10)
SQL> exec :val := 'KING'

PL/SQL procedure successfully completed.

SQL> SELECT DISTINCT SUBSTR (:val, 1, 11) "Searchword",
  2    SUBSTR (table_name, 1, 14) "Table",
  3    SUBSTR (column_name, 1, 14) "Column"
  4  FROM cols,
  5    TABLE (xmlsequence (dbms_xmlgen.getxmltype ('select '
  6    || column_name
  7    || ' from '
  8    || table_name
  9    || ' where upper('
 10    || column_name
 11    || ') like upper(''%'
 12    || :val
 13    || '%'')' ).extract ('ROWSET/ROW/*') ) ) t
 14  ORDER BY "Table"
 15  /

Searchword  Table          Column
----------- -------------- --------------
KING        EMP            ENAME

SQL>

SQL> variable val NUMBER
SQL> exec :val := 20

PL/SQL procedure successfully completed.

SQL> SELECT DISTINCT SUBSTR (:val, 1, 11) "Searchword",
  2    SUBSTR (table_name, 1, 14) "Table",
  3    SUBSTR (column_name, 1, 14) "Column"
  4  FROM cols,
  5    TABLE (xmlsequence (dbms_xmlgen.getxmltype ('select '
  6    || column_name
  7    || ' from '
  8    || table_name
  9    || ' where upper('
 10    || column_name
 11    || ') like upper(''%'
 12    || :val
 13    || '%'')' ).extract ('ROWSET/ROW/*') ) ) t
 14  ORDER BY "Table"
 15  /

Searchword  Table          Column
----------- -------------- --------------
20          DEPT           DEPTNO
20          EMP            DEPTNO
20          EMP            HIREDATE
20          SALGRADE       HISAL
20          SALGRADE       LOSAL

SQL>