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Oracle 如何基于状态连接表记录？

oracle oracle11g

Oracle 如何基于状态连接表记录？,oracle,oracle11g,left-join,oracle-sqldeveloper,Oracle,Oracle11g,Left Join,Oracle Sqldeveloper,我有一个表，它必须根据状态连接到另一个表。以下是表1数据的示例： ROWID STATE 34 TX 56 NY 67 WA 89 TX 表1中的每一行都有状态值。表2为每个州提供了两条记录。下面是一个例子： ROWID STATE NAME 19 TX Chuck, Brown 20 TX Nick, Johnes 如表2所示，德克萨斯州有两项记录。如果我使用左外连接并尝试执行以下操作

我有一个表，它必须根据状态连接到另一个表。以下是表1数据的示例：

ROWID  STATE 
 34     TX
 56     NY
 67     WA
 89     TX
表1中的每一行都有状态值。表2为每个州提供了两条记录。下面是一个例子：

ROWID   STATE       NAME  
 19      TX     Chuck, Brown
 20      TX     Nick, Johnes
如表2所示，德克萨斯州有两项记录。如果我使用
左外连接
并尝试执行以下操作：

LEFT OUTER JOIN Table 2 TB2
   ON TB1.STATE = TB2.SATE

34 TX Chuck, Brwon
34 TX Nick, Johnes
89 TX Chuck, Brwon
89 TX Nick, Johnes
然后输出将如下所示：

LEFT OUTER JOIN Table 2 TB2
   ON TB1.STATE = TB2.SATE

34 TX Chuck, Brwon
34 TX Nick, Johnes
89 TX Chuck, Brwon
89 TX Nick, Johnes
每一行都是重复的，因为表1中有两条德克萨斯州的记录。表2中有两条德克萨斯州的记录。我想看到的是：

ROWID   STATE     NAME 1         NAME 2
 34      TX    Chuck, Brwon    Nick, Johnes
基本上我想把两行合并成一行，然后加入表1。我最近开始做这个项目，我们使用Oracle数据库。如果有人知道实现这一目标的好方法，请让我知道。谢谢。

基于示例所需的输出，我将输出限制为表1中的第一个状态实例，并按ID对数据透视名称进行排序，尽管这恰好与给定示例数据的名称字段的alpha顺序相匹配

看到这个了吗

Oracle 11g R2架构设置：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
请注意，在Oracle中，ROWID是一个保留名称，因此我将其更改为ID

查询1：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
查询2：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
基于示例所需的输出，我将输出限制为表1中的第一个state实例，并按ID对数据透视名称进行排序，尽管这恰好与给定示例数据的name字段的alpha顺序相匹配

看到这个了吗

Oracle 11g R2架构设置：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
请注意，在Oracle中，ROWID是一个保留名称，因此我将其更改为ID

查询1：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
查询2：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
：

select t1.id
     , t2.state
     , t2.name
  from (select min(id) id, state from table1 group by state) t1
  join table2 t2
    on t1.state = t2.state

| ID | STATE |         NAME |
|----|-------|--------------|
| 34 |    TX | Nick, Johnes |
| 34 |    TX | Chuck, Brown |

with t1(id, state) as (
  select min(id) id, state from table1 group by state
), t2 as (   
  select state
       , row_number() over (partition by state order by name) rn
       , name
    from table2
)
select t1.id
     , pvt.*
  from t1
  join t2 pivot (max(name) for rn in (1 name_1,2 name_2)) pvt
    on t1.state = pvt.state

| ID | STATE |       NAME_1 |       NAME_2 |
|----|-------|--------------|--------------|
| 34 |    TX | Chuck, Brown | Nick, Johnes |
正如你在问题下的一条评论中所说，你会接受一个单一的、连接的名称列，这里有一个选项；我使用CTE创建表，所以需要从第13行开始

SQL> with
  2  t1 (rid, state) as
  3    (select 34, 'TX' from dual union all
  4     select 56, 'NY' from dual union all
  5     select 67, 'WA' from dual union all
  6     select 89, 'TX' from dual
  7    ),
  8  t2 (rid, state, name) as
  9    (select 19, 'TX', 'Chuck, Brown' from dual union all
 10     select 20, 'TX', 'Nick, Johnes' from dual
 11    ),
 12  -- start here
 13  it2 as
 14    (select state, listagg(name, ' & ') within group (order by null) name
 15     from t2
 16     group by state
 17    )
 18  select min(t1.rid) rid,
 19    t1.state,
 20    it2.name
 21  from t1 join it2 on t1.state = it2.state
 22  and t1.state = 'TX'
 23  group by t1.state, it2.name;

       RID ST NAME
---------- -- ------------------------------
        34 TX Chuck, Brown & Nick, Johnes

SQL>
正如你在问题下的一条评论中所说，你会接受一个单一的、连接的名称列，这里有一个选项；我使用CTE创建表，所以需要从第13行开始

SQL> with
  2  t1 (rid, state) as
  3    (select 34, 'TX' from dual union all
  4     select 56, 'NY' from dual union all
  5     select 67, 'WA' from dual union all
  6     select 89, 'TX' from dual
  7    ),
  8  t2 (rid, state, name) as
  9    (select 19, 'TX', 'Chuck, Brown' from dual union all
 10     select 20, 'TX', 'Nick, Johnes' from dual
 11    ),
 12  -- start here
 13  it2 as
 14    (select state, listagg(name, ' & ') within group (order by null) name
 15     from t2
 16     group by state
 17    )
 18  select min(t1.rid) rid,
 19    t1.state,
 20    it2.name
 21  from t1 join it2 on t1.state = it2.state
 22  and t1.state = 'TX'
 23  group by t1.state, it2.name;

       RID ST NAME
---------- -- ------------------------------
        34 TX Chuck, Brown & Nick, Johnes

SQL>
每个
状态
是否总是有零个、一个或两个
名称
记录？或者该数字在设计时是可变的和/或未知的？什么决定了哪个
Name
是
Name 1
还是
Name 2
？@APC表2中的状态总是有两条记录。没有什么特别的东西可以决定
名称1
或
名称2
。总是应该有两个名字。我所需要的只是将它们组合起来（例如，像这样连接Josh、Brown和Micky，Butt）。如果表1中有两条TX记录，但在最终结果中只有一条结果记录，那该怎么办呢。如何正确选择发送记录？或者，当按ROWID排序时，是否要将第一个名称与第一个TX记录合并，将第二个名称与第二个TX记录合并？@SentinelIf如果仔细查看上面的示例，您将看到具有左外部合并的当前代码是重复行。我想将同一状态的名称合并到一行中。例如，在表2中，TX应该有一条记录，名称应该是像Chuck，Brwon&Nick，Johnes这样的，或者是两列名称1和名称2。我希望这将帮助您理解我试图实现的目标。不需要外部联接，除非您希望返回表1中的所有记录，即使表2中不存在匹配的记录。请参阅下面我的答案，它提供了所需的输出，但不使用外部联接。每个
状态
是否总是有零个、一个或两个
名称
记录？或者该数字在设计时是可变的和/或未知的？什么决定了哪个
Name
是
Name 1
还是
Name 2
？@APC表2中的状态总是有两条记录。没有什么特别的东西可以决定
名称1
或
名称2
。总是应该有两个名字。我所需要的只是将它们组合起来（例如，像这样连接Josh、Brown和Micky，Butt）。如果表1中有两条TX记录，但在最终结果中只有一条结果记录，那该怎么办呢。如何正确选择发送记录？或者，当按ROWID排序时，是否要将第一个名称与第一个TX记录合并，将第二个名称与第二个TX记录合并？@SentinelIf如果仔细查看上面的示例，您将看到具有左外部合并的当前代码是重复行。我想将同一状态的名称合并到一行中。例如，在表2中，TX应该有一条记录，名称应该是像Chuck，Brwon&Nick，Johnes这样的，或者是两列名称1和名称2。我希望这将帮助您理解我试图实现的目标。不需要外部联接，除非您希望返回表1中的所有记录，即使表2中不存在匹配的记录。请参阅下面我的答案，它提供了所需的输出，但不使用外部联接。