Oracle 合并语句

我正在研究merge语句，但我无法理解其语法

假设我有这些桌子

CREATE TABLE employee (
employee_id NUMBER(5),
first_name  VARCHAR2(20),
last_name   VARCHAR2(20),
dept_no     NUMBER(2),
salary      NUMBER(10));

INSERT INTO employee VALUES (1, 'Dan', 'Morgan', 10, 100000);
INSERT INTO employee VALUES (2, 'Helen', 'Lofstrom', 20, 100000);
INSERT INTO employee VALUES (3, 'Akiko', 'Toyota', 20, 50000);
INSERT INTO employee VALUES (4, 'Jackie', 'Stough', 20, 40000);
INSERT INTO employee VALUES (5, 'Richard', 'Foote', 20, 70000);
INSERT INTO employee VALUES (6, 'Joe', 'Johnson', 20, 30000);
INSERT INTO employee VALUES (7, 'Clark', 'Urling', 20, 90000);

CREATE TABLE bonuses (
employee_id NUMBER, bonus NUMBER DEFAULT 100);

INSERT INTO bonuses (employee_id) VALUES (1);
INSERT INTO bonuses (employee_id) VALUES (2);
INSERT INTO bonuses (employee_id) VALUES (4);
INSERT INTO bonuses (employee_id) VALUES (6);
INSERT INTO bonuses (employee_id) VALUES (7);
COMMIT;

作为一个例子，我想用200*employee_id更新所有奖金条目。怎么了

merge into bonuses b
using
  (select employee_id id, 200 bonus from employees) test
on (test.id = b.employee_id)
when matched then update set
b.bonus = test.bonus * test.employee_id

谢谢

另请参见我的sqlfiddle：

两个小错误：

1） 员工代替员工

---

2） test.id代替test.employee\u id

谢谢！很高兴看到只是打字错误

merge into bonuses b
using
  (select employee_id id, 200 bonus from employee) test
on (test.id = b.employee_id)
when matched then update set
b.bonus = test.bonus * test.id;