Oracle10g Oracle:从两个表中选择

Oracle10g Oracle:从两个表中选择,oracle10g,Oracle10g,我有两个表EMPLOYEE和DEPARTMENT 部门表的列: DEPARTMENT_ID DEPARTMENT_NAME MANAGER_ID LOCATION_ID EMPLOYEE表的列 EMPLOYEE_ID FIRST_NAME LAST_NAME EMAIL PHONE_NUMBER HIRE_DATE DATE JOB_ID SALARY COMMISSION_PCT MANAGER_ID DEPARTMENT_ID 当显示所需号码时,选择员工ID FIRST_NAME

我有两个表
EMPLOYEE
DEPARTMENT

部门
表的列:

 DEPARTMENT_ID
 DEPARTMENT_NAME
 MANAGER_ID
 LOCATION_ID
EMPLOYEE
表的列

EMPLOYEE_ID
FIRST_NAME
LAST_NAME
EMAIL
PHONE_NUMBER
HIRE_DATE DATE
JOB_ID
SALARY
COMMISSION_PCT
MANAGER_ID
DEPARTMENT_ID
当显示所需号码时,选择员工ID

FIRST_NAME
LAST_NAME
EMAIL
PHONE_NUMBER
HIRE_DATE DATE
JOB_ID
SALARY
COMMISSION_PCT
MANAGER_ID
DEPARTMENT_ID

请执行此查询

select 
    emp.first_name, emp.last_name, emp.email, emp.phone_number, 
    dept.manager_id 
from 
    employee emp, department dept 
where 
    emp.department_id = dept.department_id

1) 请修理你的语法,先生!2) 那么你的问题是什么?我想在他选择DEPARTMENT_id时显示Employees表中的所有现有字段,以便您需要:选择*from epmloyee,其中DEPARTMENT_id=?是,感谢您的努力当我选择编号时,两个表的部门id都存在。部门您自己的字段在员工表中显示ORA-00942:表或视图不存在当我选择编号时,两个表的部门id都存在。部门您自己的字段在员工表中显示我-老式的逗号分隔表列表在ANSI-92 SQL标准(20多年前)中,样式被正确的ANSI
JOIN
语法所取代,不鼓励使用。从员工emp中选择emp.first\u name、emp.last\u name、emp.email、emp.phone\u number、dept.DEPARTMENT\u ID=90,其中emp.DEPARTMENT\u ID=dept.DEPARTMENT\u ID