Kohana ORM关系和显示信息
我不知道该怎么做 假设我有3个模型,A、B和C 模型A有许多C,模型B有许多C,C属于A和B 我得到了所有的BKohana ORM关系和显示信息,orm,kohana,Orm,Kohana,我不知道该怎么做 假设我有3个模型,A、B和C 模型A有许多C,模型B有许多C,C属于A和B 我得到了所有的B $getBs=ORM::factory('B')->find_all(); 我显示A、B、C foreach($getBs as $getB) { echo $getB->b_category_title; foreach($getB->C->find_all() as $getC) { echo $getC->
$getBs=ORM::factory('B')->find_all();
我显示A、B、C
foreach($getBs as $getB)
{
echo $getB->b_category_title;
foreach($getB->C->find_all() as $getC)
{
echo $getC->c_title;
echo $getA->a_author; //Problem part
}
}
在显示模型C的信息时,我不知道如何访问模型A并将其连接到模型C
编辑
为了获得工作代码,我将模型A-C更改为模型1-3
使用biakaveron的_load_with示例,我得到以下错误:
Database_Exception [ 1054 ]: Unknown column 'three.id_c' in 'on clause' [ SELECT `ones`.`a_id` AS `ones:a_id`, `ones`.`a_author` AS `ones:a_author`, `three`.* FROM `threes` AS `three` JOIN `twos_threes` ON (`twos_threes`.`id_c` = `three`.`c_id`) LEFT JOIN `ones` AS `ones` ON (`ones`.`a_id` = `three`.`id_c`) WHERE `twos_threes`.`id_b` = '1' ]
型号:
class Model_One extends ORM {
protected $_primary_key = 'a_id';
protected $_has_many = array(
'threes'=> array(
'model' => 'three',
'through' => 'ones_threes',
'far_key' => 'id_c',
'foreign_key' => 'id_a'
),
);
}
class Model_Two extends ORM {
protected $_primary_key = 'b_id';
protected $_has_many = array(
'threes'=> array(
'model' => 'three',
'through' => 'twos_threes',
'far_key' => 'id_c',
'foreign_key' => 'id_b'
),
);
}
class Model_Three extends ORM {
protected $_primary_key = 'c_id';
protected $_belongs_to = array(
'ones'=> array(
'model' => 'one',
'through' => 'ones_threes',
'far_key' => 'id_a',
'foreign_key' => 'id_c'
),
'twos'=> array(
'model' => 'two',
'through' => 'twos_threes',
'far_key' => 'id_b',
'foreign_key' => 'id_c'
),
);
protected $_load_with = array('ones');
}
为什么要找三个身份证
C属于A和B
附言,只是一张纸条。您可以使用$\u load\u和属性加载C和A对象:
class Model_C extends ORM {
// ...
protected $_load_with = array('A');
// ...
}
只是好奇\u load\u with
属性是如何工作的?假设表C通过列“a_id”与表a有关系。科哈纳如何与这一切相匹配?表名和列名是否需要特殊格式?$\u load\u with
只包含一个关系别名,在$\u-beliens\u-to
属性中有详细说明。这与加载模型之前使用('A')
调用->相同。当我使用_load_with属性时,我遇到了一个错误。我在帖子中添加了错误。为什么'foreign\u key'=>'id\u c'
?我想应该是'foreign\u key'=>'c\u id'
。检查您的外键名称。
class Model_C extends ORM {
// ...
protected $_load_with = array('A');
// ...
}