Pandas 使用datetime在ipython中切片数据
我从RBR.csv创建了一个dataframe df2,只希望在开始:18-04-2015 21:30和结束:18-09-2015 14:09之间使用数据,设置为dataframe df3Pandas 使用datetime在ipython中切片数据,pandas,ipython,Pandas,Ipython,我从RBR.csv创建了一个dataframe df2,只希望在开始:18-04-2015 21:30和结束:18-09-2015 14:09之间使用数据,设置为dataframe df3 In [12]: df3 = df2[(df2['date']>=datetime.datetime(18-04-2015 21:30)) & (df2['date'] <= datetime.datetime(18-09-2015 14:09))] File "
In [12]:
df3 = df2[(df2['date']>=datetime.datetime(18-04-2015 21:30)) &
(df2['date'] <= datetime.datetime(18-09-2015 14:09))]
File "<ipython-input-12-95bbb0030f0a>", line 1
df3 = df2[(df2['date']>=datetime.datetime(18-04-2015 21:30)) &
(df2['date'] <= datetime.datetime(18-09-2015 14:09))]
^
SyntaxError: invalid syntax
[12]中的
df3=df2[(df2['date']>=datetime.datetime(18-04-2015 21:30))&
(df2['date']=datetime.datetime(18-04-2015 21:30))&
(df2['date']您需要正确创建datetime.datetime
实例:
df3 = df2[(df2['date'] >= datetime.datetime(2015, 4, 18, 21, 30)) &
(df2['date'] <= datetime.datetime(2015, 9, 18, 14, 9))]
df3=df2[(df2['date']>=datetime.datetime(2015,4,18,21,30))&
(df2['date']='18-04-2015 21:30')和(df2['date']您需要正确创建datetime.datetime
实例:
df3 = df2[(df2['date'] >= datetime.datetime(2015, 4, 18, 21, 30)) &
(df2['date'] <= datetime.datetime(2015, 9, 18, 14, 9))]
df3=df2[(df2['date']>=datetime.datetime(2015,4,18,21,30))&
(df2['date']='18-04-2015 21:30')和(df2['date']请正确格式化您的问题!另外,添加带问题的句子!(……?)阅读,如何在堆栈溢出(SO)上提问。没有它,主持人会很快删除您的问题。请正确格式化您的问题!另外,添加带问题的句子!(……?)阅读,如何询问堆栈溢出(SO)。没有它,版主会很快删除您的问题。谢谢@Mike Müller。谢谢@Mike Müller。