Pandas 将行值与表中的列值匹配

我想将“分类类型”列中的值与以下列中的值相匹配

我想要一个包含所有值的列表作为结果

  Holding Period      Classification Type                        Optimization & Gap Risk                                   Directional Risk
0     Short Term  Optimization & Gap Risk                      Frequency of Optimization                                   Beta Calibration
1    Medium Term         Directional Risk        Frequency of Data Input for alpha model                frequency of Beta or $ Rebalanciing
2      Long Term            Concentration  Ability to React to Change in Market Risk/Vol  Is beta/$ neutrality controlled through index,...

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我希望这能说明我想要什么。基本上是列中与“分类类型”列中的值具有相同名称的所有值的聚合。

我将这样做

我将通过捕获列中的所有值作为列表，为这两个列创建一个字典

• 优化与缺口风险
• 定向风险

您可以按如下方式执行此操作：

  Holding Period      Classification Type     List
0     Short Term  Optimization & Gap Risk     ['Frequency of Optimization', 'Frequency of Data Input for alpha model', 'Ability to React to Change in Market Risk/Vol']
1    Medium Term         Directional Risk     ['Beta Calibration', 'frequency of Beta or $ Rebalanciing', 'Is beta/$ neutrality controlled through index, options or single name positions?']
2      Long Term            Concentration     NA

然后我将

分类类型

列映射到字典。那会给你你想要的

完整代码为：

riskdict = {}
for col in df.columns[2:]:
    riskdict[col] = df[col].tolist()

其输出将为：

riskdict = {}
for col in df.columns[2:]:
    riskdict[col] = df[col].tolist()

df['List'] = df['Classification Type'].map(riskdict)
print (df)

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请提供一个。我提供的数据框无法帮助您自己？优化和差距风险，方向风险是“分类类型”列中的值，而不是列名。您可以使用索引，

cols=list（df['Classification Type'].values）

，然后

df[cols]

。

  Holding Period  ...                                               List
0     Short Term  ...  [Frequency of Optimization, Frequency of Data ...
1    Medium Term  ...  [Beta Calibration, frequency of Beta or $ Reba...
2      Long Term  ...                                                NaN