用perl/awk连接虚线

我有一个包含sql语句的大文件，如：

PP3697HB @@@@0
<<<<<<Record has been deleted as per PP3697HB>>>>>>
FROM sys.xtab_ref rc,sys.xtab_sys f,sys.domp ur WHE
RE rc.milf = ur.milf  AND rc.molf = f.molf AND ur.dept = 'SWIT'AND ur
.department = 'IND' AND share = '2' AND ur.status = 'DONE' AND f.s
tatus = 'TRUE' AND rc.OPERATOR = '=' AND rc.VALUE = '261366'AND rc.r
unet IN (SELECT milf FROM sys.domp WHERE change = 'OVO' A
ND IND = 75);

我需要把所有这些断线重新组合成一行

这条线应该是这样的：

PP3697HB @@@@0<<<<<<Record has been deleted as per PP3697HB>>>>>>FROM sys.xtab_ref rc,sys.xtab_sys f,sys.domp ur WHERE rc.milf = ur.milf  AND rc.molf = f.molf AND ur.dept = 'SWIT'AND ur.department = 'IND' AND share = '2' AND ur.status = 'DONE' AND f.status = 'TRUE' AND rc.OPERATOR = '=' AND rc.VALUE = '261366'AND rc.runet IN (SELECT milf FROM sys.domp WHERE change = 'OVO' AND IND = 75);

如何在perl/awk中实现这一点

我们可以说，行的开头必须是^PP.*，sql语句的结尾必须是。*$

---

如果您理解此问题有困难，请告诉我，我将再次尝试解释。

请尝试使用Perl实现此解决方案：

#!/usr/bin/perl -w    
use strict;
use warnings;
use Data::Dumper;

## The raw string
my $str = "                                                                                                                                                                                                                                  
PP3697HB @@@@0                                                                                                                                                                                                                               
<<<<<<Record has been deleted as per PP3697HB>>>>>>                                                                                                                                                                                          
FROM sys.xtab_ref rc,sys.xtab_sys f,sys.domp ur WHE                                                                                                                                                                                          
RE rc.milf = ur.milf  AND rc.molf = f.molf AND ur.dept = 'SWIT'AND ur                                                                                                                                                                        
.department = 'IND' AND share = '2' AND ur.status = 'DONE' AND f.s                                                                                                                                                                           
tatus = 'TRUE' AND rc.OPERATOR = '=' AND rc.VALUE = '261366'AND rc.r                                                                                                                                                                         
unet IN (SELECT milf FROM sys.domp WHERE change = 'OVO' A                                                                                                                                                                                    
         ND IND = 75);                                                                                                                                                                                                                       
";

## Split the given string as per new line.
my @lines = split(/\n/, $str);

## Join every element of the formed array using blank.
$str = join("", @lines);

print $str;

Perl解决方案：

perl -ne 'chomp $last unless /^PP/; print $last; $last = $_ }{ print $last' FILE.SQL

试试这一行：

awk '!/;$/{printf "%s",$0}/;$/{print}' file

使用tr删除换行符，使用sed拆分每条SQL语句：

tr '\n' ' ' < file | sed 's/;/;\n/g'

---

假设有其他线没有像这样分开，并且只有指定的线需要重新连接：

awk '
    /^PP/ {insql=1}
    /;$/  {insql=0}
    insql {printf "%s", $0; next}
          {print}
' file