Php 使用数组\计数\值获取两个相同的值

我有一个数组，我想得到所有不同的值

我的代码运行良好，直到有一点

$array_for_19_2=[
["A 1","A 1","A 1","A 2","A 3","A 2","A 1","A 3","A 2","A 1","A 3","A 3","A 2","A 1","A 2"],
["A a","A a","A c","A a","A c","A c","A c","A a","A a","A c","A c","A a","A a","A a","A c"],
["A X","A Y","A Z","A Z","A Z","A Y","A X","A X","A X","A X","A Z","A Z","A X","A Z","A Y"],
["1 a","1 b","1 a","1 a","1 b","1 c","1 b","1 c","1 b","1 a","1 a","1 c","1 b","1 a","1 a"],
["2 a","2 a","2 a","2 a","2 a","2 a","2 a","2 b","2 b","2 a","2 a","2 b","2 a","2 b","2 b"],
["3 b","3 c","3 b","3 c","3 a","3 b","3 c","3 b","3 b","3 b","3 c","3 c","3 a","3 c","3 b"],
["a X","a X","a Z","a Y","a Z","a X","a Y","a Z","a Z","a Z","a X","a X","a Y","a Y","a Z"],
["b Z","b Z","b X","b Z","b Z","b Z","b Z","b X","b Y","b Y","b X","b X","b Y","b Y","b Z"],
["c Y","c Y","c Y","c Y","c Z","c Z","c X","c X","c Z","c Y","c Y","c X","c Z","c Y","c X"],
["1 Z","1 Z","1 X","1 Y","1 X","1 Z","1 X","1 Y","1 Y","1 Z","1 X","1 Z","1 Y","1 Y","1 Y"],
["2 X","2 X","2 Y","2 Z","2 Y","2 X","2 X","2 Z","2 Y","2 Y","2 Y","2 X","2 Y","2 X","2 X"],
["3 X","3 X","3 Y","3 X","3 Y","3 Y","3 Y","3 X","3 Z","3 X","3 X","3 Y","3 Y","3 X","3 Y"]];

foreach (array_count_values($array[$i]) as $key => $value) {
                if(strrpos($key, "A")===0 && is_numeric(substr($key,2)))
                {$keycount1++;}
                else if(strrpos($key, "A")===0 && !is_numeric(substr($key,2))){
                array_push($lettersarray, substr($key, 2)); 
                }
                $probabilty=round(($value/count($array[$i])),2);
                echo "$key - <strong>$value</strong> <br/>Probability: $probabilty<br/>"; 
                $names=str_replace(' ', '', $key);
                $newarray[$key]=$probabilty;

        }

---

为什么要两次获得相同的值？

这将返回所有值的计数

$res = array_icount_values ($array);
echo '<pre>';print_r($res);

function array_icount_values($arr, $lower = true) {
    $arr2 = array();
    if (!is_array($arr['0'])) {
        $arr = array($arr);
    }
    foreach ($arr as $k => $v) {
        foreach ($v as $v2) {
            if ($lower == true) {
                $v2 = strtoupper($v2);
            }
            if (!isset($arr2[$v2])) {
                $arr2[$v2] = 1;
            } else {
                $arr2[$v2]++;
            }
        }
    }
    return $arr2;
}

$res=array\u icount\u值（$array）；
回声'；印刷品(港币);；
函数数组\u i计数\u值（$arr，$lower=true）{
$arr2=数组（）；
如果（！is_数组（$arr['0']））{
$arr=阵列（$arr）；
}
foreach（$arr为$k=>$v）{
foreach（$v作为$v2）{
如果（$lower==true）{
$v2=strtoupper（$v2）；
}
如果（！isset（$arr2[$v2]））{
$arr2[$v2]=1；
}否则{
$arr2[$v2]++；
}
}
}
返回$2；
}

我不明白你想要什么。你能澄清一下吗？我试试看。我有一个数组，我需要得到所有的唯一值，以及它们有多少，然后计算每个唯一值的概率。顺便说一句，一些代码做了一些其他的事情。代码对我来说很好，请看，谢谢Paul尝试。我明白了，它是有效的，但是为什么它不适合我。。。字母都是一样的（我的意思是没有其他语言的字母），但我得到了错误的结果…这可能会帮助你。它将返回所有值的计数，直到得到相同的结果

$res = array_icount_values ($array);
echo '<pre>';print_r($res);

function array_icount_values($arr, $lower = true) {
    $arr2 = array();
    if (!is_array($arr['0'])) {
        $arr = array($arr);
    }
    foreach ($arr as $k => $v) {
        foreach ($v as $v2) {
            if ($lower == true) {
                $v2 = strtoupper($v2);
            }
            if (!isset($arr2[$v2])) {
                $arr2[$v2] = 1;
            } else {
                $arr2[$v2]++;
            }
        }
    }
    return $arr2;
}