Php 在第二个查询中使用查询结果
我试图在第二个查询中使用一个查询的结果作为WHERE的一部分。我不确定如何最好地解决这个问题,非常感谢您的帮助: 第一个问题:Php 在第二个查询中使用查询结果,php,mysql,join,Php,Mysql,Join,我试图在第二个查询中使用一个查询的结果作为WHERE的一部分。我不确定如何最好地解决这个问题,非常感谢您的帮助: 第一个问题: $result = mysql_query("SELECT `keyword` FROM `history` ORDER BY `last_update` ASC LIMIT 1 "); while($row = mysql_fetch_array($result)) $keyword = $row['keyword']; 第二个问题 $result = mysql_
$result = mysql_query("SELECT `keyword` FROM `history` ORDER BY `last_update` ASC LIMIT 1 ");
while($row = mysql_fetch_array($result))
$keyword = $row['keyword'];
第二个问题
$result = mysql_query("SELECT `id` FROM `data_store` WHERE `keyword`= [result from my first query] ORDER BY `id` DESC LIMIT 1");
while($row = mysql_fetch_array($result))
$id = $row['id'];
为了澄清,keyword.data\u存储与keyword.history相关使用子查询
$result = mysql_query("
SELECT `id`
FROM `data_store`
WHERE `keyword` = (SELECT `keyword`
FROM `history`
ORDER BY `last_update` ASC
LIMIT 1)
ORDER BY `id` DESC");
while($row = mysql_fetch_array($result))
$id = $row['id'];
使用子查询
$result = mysql_query("
SELECT `id`
FROM `data_store`
WHERE `keyword` = (SELECT `keyword`
FROM `history`
ORDER BY `last_update` ASC
LIMIT 1)
ORDER BY `id` DESC");
while($row = mysql_fetch_array($result))
$id = $row['id'];
(剥离了PHP方面,因为它不相关)
(剥离了PHP方面,因为它不相关)
SELECT `id` FROM `data_store` WHERE
`keyword` IN (
SELECT `keyword` FROM `history` ORDER BY `last_update` ASC LIMIT 1
)
ORDER BY `id` DESC LIMIT 1