PHP-通过一种形式的多个输入上传多个文件
我有一个脚本,允许我上传数据库中产品的照片。我想通过同一表单上传多个产品的照片。我构造了一个动态表单,每个产品有一个文件输入,产品id作为标识符。由于某种原因,当我试图在另一端接收文件时,我并没有得到所有信息。这是我的密码…有什么想法吗PHP-通过一种形式的多个输入上传多个文件,php,forms,file-upload,Php,Forms,File Upload,我有一个脚本,允许我上传数据库中产品的照片。我想通过同一表单上传多个产品的照片。我构造了一个动态表单,每个产品有一个文件输入,产品id作为标识符。由于某种原因,当我试图在另一端接收文件时,我并没有得到所有信息。这是我的密码…有什么想法吗 <form class="form-signin" action="products_csv.php" method="POST" enctype="multipart/form-data" style="max-width:600px !import
<form class="form-signin" action="products_csv.php" method="POST" enctype="multipart/form-data" style="max-width:600px !important">
<h2 class="form-signin-heading">Upload Photos</h2>
<h4>Product #1</h4>
<input type="hidden" name="product_ids[]" value="23" ?>
<input type="file" class="form-control" name="photos[23][]" id="photos" multiple><br /><br />
<h4>Product #2</h4>
<input type="hidden" name="product_ids[]" value="24" ?>
<input type="file" class="form-control" name="photos[24][]" id="photos" multiple><br /><br />
<h4>Product #3</h4>
<input type="hidden" name="product_ids[]" value="25" ?>
<input type="file" class="form-control" name="photos[25][]" id="photos" multiple><br /><br />
<h4>Product #4</h4>
<input type="hidden" name="product_ids[]" value="26" ?>
<input type="file" class="form-control" name="photos[26][]" id="photos" multiple><br /><br />
<h4>Product #5</h4>
<input type="hidden" name="product_ids[]" value="27" ?>
<input type="file" class="form-control" name="photos[27][]" id="photos" multiple><br /><br />
<h4>Product #6</h4>
<input type="hidden" name="product_ids[]" value="28" ?>
<input type="file" class="form-control" name="photos[28][]" id="photos" multiple><br /><br />
<button class="btn btn-large btn-primary" type="submit">Upload</button>
</form>
以下是PHP代码:
foreach($_POST as $key => $value) {
$$key = $value;
}
//Upload photos and link to records in DB
$path = "uploads/"; // Upload directory
$total_count = 0;
$total_products = 0;
foreach($product_ids as $key => $value) {
$query = "SELECT * FROM `variants_queue` WHERE `id` = '$value'";
$rs = mysql_query($query,$con);
$row = mysql_fetch_row($rs);
$sku = $row[1];
$num_of_photos = count($_FILES["photos"]['name'][$value]);
$count = 0;
for($i=0;$i<=$num_of_photos-1;$i++) {
$filename = $path.$sku."-".$i.".jpg";
$filesize = $_FILES['photos']['size'][$value][$i];
if($filesize > 0) {
move_uploaded_file($_FILES['photos']["tmp_name"][$value][$i], $filename);
$query2 = "INSERT INTO `variants_photos_queue` (variants_queue_id,filename,size) VALUES ('$value','$filename','$filesize')";
$rs2 = mysql_query($query2,$con);
$count++;
}
}
}
这是完整的密码吗?
$product\u ID没有任何引用
请像这样试试。HTML:
<form class="form-signin" action="products_csv.php" method="POST" enctype="multipart/form-data" style="max-width:600px !important">
<h2 class="form-signin-heading">Upload Photos</h2>
<h4>Product #1</h4>
<input type="hidden" name="product_ids[]" value="23" ?>
<input type="file" class="form-control" name="photos[]" id="photos" multiple><br /><br />
<h4>Product #2</h4>
<input type="hidden" name="product_ids[]" value="24" ?>
<input type="file" class="form-control" name="photos[]" id="photos" multiple><br /><br />
<h4>Product #3</h4>
<input type="hidden" name="product_ids[]" value="25" ?>
<input type="file" class="form-control" name="photos[]" id="photos" multiple><br /><br />
<h4>Product #4</h4>
<input type="hidden" name="product_ids[]" value="26" ?>
<input type="file" class="form-control" name="photos[]" id="photos" multiple><br /><br />
<h4>Product #5</h4>
<input type="hidden" name="product_ids[]" value="27" ?>
<input type="file" class="form-control" name="photos[]" id="photos" multiple><br /><br />
<h4>Product #6</h4>
<input type="hidden" name="product_ids[]" value="28" ?>
<input type="file" class="form-control" name="photos[]" id="photos" multiple><br /><br />
<button class="btn btn-large btn-primary" type="submit">Upload</button>
</form>
PHP:
我怎么知道哪张照片属于哪一个产品id?它是用文件输入上方的隐藏输入映射的。我更改了代码,删除了foreach中的for循环。好的,但是每个输入可以有多张照片…这不是每个文件输入只抓取一张照片吗?
<?php
$path = "uploads/"; // Upload directory
$total_count = 0;
$total_products = 0;
$product_ids = $_POST["product_ids"];
foreach($product_ids as $key => $value) {
$query = "SELECT * FROM `variants_queue` WHERE `id` = '$value'";
$rs = mysql_query($query,$con);
$row = mysql_fetch_row($rs);
$sku = $row[1];
$num_of_photos = count($_FILES["photos"]);
$count = 0;
$filename = $path.$sku."-".$key.".jpg";
$filesize = $_FILES['photos']['size'][$key];
if($filesize > 0) {
move_uploaded_file($_FILES['photos']["tmp_name"][$key], $filename);
$query2 = "INSERT INTO `variants_photos_queue` (variants_queue_id,filename,size) VALUES ('$value','$filename','$filesize')";
$rs2 = mysql_query($query2,$con);
$count++;
}
}
?>