Php 使用CURL将JSON数据发布到API
当我使用Php 使用CURL将JSON数据发布到API,php,json,api,curl,Php,Json,Api,Curl,当我使用curl将json数据发布到API时,我没有得到任何输出。我想向收件人发送电子邮件邀请 $url_send ="http://api.address.com/SendInvitation?"; $str_data = json_encode($data); function sendPostData ($url, $post) { $ch = curl_init($url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true)
curl
将json
数据发布到API时,我没有得到任何输出。我想向收件人发送电子邮件邀请
$url_send ="http://api.address.com/SendInvitation?";
$str_data = json_encode($data);
function sendPostData ($url, $post) {
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($post));
return curl_exec($ch);
}
这里是JSON
$stru data
[
{
"authorizedKey" : "abbad35c5c01-xxxx-xxx",
"senderEmail" : "myemail@yahoo.com",
"recipientEmail" : "jaketalledo86@yahoo.com",
"comment" : "Invitation",
"forceDebitCard" : "false"
}
]
和调用函数:
$response = sendPostData($url_send, $str_data);
这是API:尝试添加
curl\u setopt($ch,curloopt\u FOLLOWLOCATION,1)代码>
并将http\u build\u查询($post)
更改为$post
实施:
<?php
$data = array(
"authorizedKey" => "abbad35c5c01-xxxx-xxx",
"senderEmail" => "myemail@yahoo.com",
"recipientEmail" => "jaketalledo86@yahoo.com",
"comment" => "Invitation",
"forceDebitCard" => "false"
);
$url_send ="http://api.payquicker.com/api/SendInvitation?authorizedKey=xxxxx";
$str_data = json_encode($data);
function sendPostData($url, $post){
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POSTFIELDS,$post);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
$result = curl_exec($ch);
curl_close($ch); // Seems like good practice
return $result;
}
echo " " . sendPostData($url_send, $str_data);
?>
但也许它会在有效数据下工作
编辑:
对于发布xml,
它与他们的站点上的相同,只是字符串不同:
$xml = '
<SendInvitationRequest xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/PQApi.Models">
<authorizedKey>80c587b9-caa9-4e56-8750-a34b17dba0a2</authorizedKey>
<comment>sample string 4</comment>
<forceDebitCard>true</forceDebitCard>
<recipientEmail>sample string 3</recipientEmail>
<senderEmail>sample string 2</senderEmail>
</SendInvitationRequest>';
您必须添加标题:
$headers= array('Accept: application/json','Content-Type: application/json');
以及:
否则
HTTP状态415-不支持的媒体类型
。。。可能发生。您不需要像以前那样添加头json\u encode
。
只是print_r(curl_getinfo($ch))代码>并查看其中的内容类型信息。我刚刚在他们的api上读到“请用?authorizedKey=xxxxx将其附加到url”,我将更改上面的代码,我需要用我的身份验证密钥分配该xxxx吗?我仍然收到{“success”:false,“errorMessage”:“对象引用未设置为对象的实例。”,“status”:“N/A”}我试着联系那里的it支持人员,因为我仍然会遇到这个错误。非常感谢你花时间回答我的问题。希望你能解决这个问题-我想尝试使用xml而不是json,因为我尝试了他们使用xml的另一个api调用,结果成功了。
sendPostData($url_send, $xml)
$headers= array('Accept: application/json','Content-Type: application/json');
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);