Php 多个同名文本输入-添加到数据库
我有一个有几个字段的表单,所有字段都可以相乘Php 多个同名文本输入-添加到数据库,php,arrays,post,input,foreach,Php,Arrays,Post,Input,Foreach,我有一个有几个字段的表单,所有字段都可以相乘 <input type="text" name="child_name[]" /> <input type="text" name="child_age[]" /> <input type="text" name="child_gender[]" /> <input type="text" name="child_school[]" /> 当我打印出数据时,它将所有字段显示为数组,所以我肯定是
<input type="text" name="child_name[]" />
<input type="text" name="child_age[]" />
<input type="text" name="child_gender[]" />
<input type="text" name="child_school[]" />
当我打印出数据时,它将所有字段显示为数组,所以我肯定是对foreach语句做了一些错误,但我不知道是什么
Array ( [child_name] => Array ( [0] => child one [1] => child two) [child_age] => Array ( [0] => 14 [1] => 13 ) [child_gender] => Array ( [0] => male [1] => female ) [child_school] => Array ( [0] => burnside [1] => summer heights high ) )
任何帮助都将不胜感激#
更新
这是我的foreach的代码
foreach ($_POST['child_name'] as $child_name)
{
$insert_children_data = array(
'child_name' => $_POST['child_name'],
'child_age' => $_POST['child_age'],
'child_gender' => $_POST['child_gender'],
'child_school' => $_POST['child_school']
);
$insert = $this->db->insert('portrait_children', $insert_children_data);
return $insert;
}
试试这个(假设您的表单为每个child\u name、child\u age等获得相同数量的元素):
对于($ix=0;$ix$\u POST['child\u name'][$ix],
'child_age'=>$\u POST['child_age'][$ix],
“儿童性别”=>$\u POST['child\u gender'][$ix],
“儿童学校”=>$\u POST['child\u school'][$ix]
);
$insert=$this->db->insert('纵向儿童',$insert儿童数据);
//返回$insert//你不能回到这里。必须让循环完成。
}
如果要将数组分配给键,这是不可行的,请尝试循环所有元素
foreach ($_POST as $key)<br>
{<br>
foreach($key as $v=>$v1)<br>
{<br>
$s[$v] = $v1;<br>
}<br>
}<br>
print_r($s);
foreach($\u发布为$key)
{
foreach($v=>v1的键)
{
$s[$v]=$v1;
}
}
印刷品(港币);;
制作一个数组。数组包含特定子类的所有数据
Array (
[0] => Array (
[name] => child1
[age] => 5
[gender] => male
[school] => 1school )
[1] => Array (
[name] => child2
[age] => 10
[gender] => male
[school] => school2 )
请尝试下面的代码
$i =0;
foreach($_REQUEST['child_name'] as $child)
{
$child1[$i]['name'] = $child;
$i++;
}
$i =0;
foreach($_REQUEST['child_age'] as $child)
{
$child1[$i]['age'] = $child;
$i++;
}
$i =0;
foreach($_REQUEST['child_gender'] as $child)
{
$child1[$i]['gender'] = $child;
$i++;
}
$i =0;
foreach($_REQUEST['child_school'] as $child)
{
$child1[$i]['school'] = $child;
$i++;
}
$insert = $this->db->insert('portrait_children', $child1);
return $insert;
请显示您的查询。您在
foreach
中有什么代码?您必须使用两个foreach
,一个用于$\u POST
字段,第二个用于key
中的字段。我在$ix=0处收到语法错误“语法错误,意外“;”;有什么想法吗?你试过最新版本了吗。请参阅上面的更新版本。我留下了一个小的打字错误,现在就把它修好了。是的,它很有效!非常感谢:)当我获得足够高的声誉时,我会投票支持你:)
Array (
[0] => Array (
[name] => child1
[age] => 5
[gender] => male
[school] => 1school )
[1] => Array (
[name] => child2
[age] => 10
[gender] => male
[school] => school2 )
$i =0;
foreach($_REQUEST['child_name'] as $child)
{
$child1[$i]['name'] = $child;
$i++;
}
$i =0;
foreach($_REQUEST['child_age'] as $child)
{
$child1[$i]['age'] = $child;
$i++;
}
$i =0;
foreach($_REQUEST['child_gender'] as $child)
{
$child1[$i]['gender'] = $child;
$i++;
}
$i =0;
foreach($_REQUEST['child_school'] as $child)
{
$child1[$i]['school'] = $child;
$i++;
}
$insert = $this->db->insert('portrait_children', $child1);
return $insert;