Php 从同一字段进行两次求和的SQL查询

我试图在“created_at”字段中按年份计算“type”=1且type=2的总“金额”

这是桌子

+-----------------+------------------+------+
| Field           | Type             | Null | 
+-----------------+------------------+------+-----
 | id              | int(10) unsigned | NO   | 

 | type            | int(10) unsigned | YES  |

 | type            | varchar(255)     | NO   | 
| amount          | double(11,2)     | NO   |                           
| created_at      | timestamp        | YES  |
| updated_at      | timestamp        | YES  |   

这是我的代码（它只给出type=1的总数）：

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提前感谢您的帮助。

您的问题需要进一步澄清，但我假设您希望将在创建的类型1每年的金额与年度总金额进行比较

select year(created_at), created_at, type,
       sum(case when type =1 then amount else 0 end) as type1amount,
       sum(amount) over (partition by year(created_at)) as yeartotal
from table
group by 1,2,3

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你只需要一个简单的查询就可以了。取日期的年份，按年份和类型对金额和组进行求和。仅供参考，您的问题中有两次将

类型

作为字段。这是不可能的，所以我第二次假设它确实是其他字段名

SELECT
    YEAR(created_at) AS year, 
    type,
    SUM(amount) AS amount
FROM mytable 
GROUP BY YEAR(created_at), type
ORDER BY YEAR(created_at)

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我怀疑您确实想要条件聚合：

SELECT YEAR(created_at) AS year, 
       SUM(CASE WHEN type = 1 THEN amount ELSE 0 END) as amount_1,
       SUM(CASE WHEN type = 2 THEN amount ELSE 0 END) as amount_2
FROM table 
GROUP BY YEAR(created_at);

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我认为您不需要对此进行子查询。谢谢您的回答，我在您之前得到了Gordon Linoff提供的解决方案

SELECT YEAR(created_at) AS year, 
       SUM(CASE WHEN type = 1 THEN amount ELSE 0 END) as amount_1,
       SUM(CASE WHEN type = 2 THEN amount ELSE 0 END) as amount_2
FROM table 
GROUP BY YEAR(created_at);